Answer:
-0.04x +17.2
Step-by-step explanation:
Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
Step-by-step explanation:
-7(-4p+1) + 2p
-7 x -4 = 28p
-7 x 1 = -7
28p + 2p = 30p
so
30p-7
Answer:
No Solutions
Step-by-step explanation:
