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Rasek [7]
3 years ago
9

Suppose the sides of a pendant are 18 mm long. what is the height of the pendant to the nearest tenth of a millimeter?

Mathematics
1 answer:
FromTheMoon [43]3 years ago
8 0

Answer is 20.8 mm long check image for full explanation

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jekas [21]

Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°

To Find: The length of the park's boundary to the nearest yard.

Calculation:

The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc

or,                    (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)

or,                    (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or,                    (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or,                    (P) = 100 yards + 209.33 yards

or,                    (P) = 309.33 yards ≈309 yards

Hence, the option D:309 yards is the correct option.

7 0
4 years ago
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Name the intersection of line qz and segment wu
Schach [20]
What?? i need a photo
3 0
3 years ago
7 . Your goal is to sell at least 50 boxes of cookies for your school fundraiser.
worty [1.4K]

Answer:

a. number of boxes sold ≥ 50

b. 26 + x ≥ 50

Step-by-step explanation:

8 0
3 years ago
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Does any one know the answer to this thank you
makvit [3.9K]

Answer:

The First choice

Step-by-step explanation:

8 0
3 years ago
A ball, with an initial position of x = 25.89 meters, undergoes a displacement of 32.2 meters. What is it’s final position?
Snowcat [4.5K]

Answer:

The answer is 58.09

Step-by-step explanation:

To get the final position, you add the displacement to the initial position.

Final position = 25.89 + 32.2

Final position = 58.09metres

4 0
4 years ago
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