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suter [353]
3 years ago
13

The sum of 2 and a number is 20

Mathematics
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:4

Step-by-step explanation:

You might be interested in
Simplify (6x2 + 11x − 3) + (2x2 − 17x − 4).
d1i1m1o1n [39]

Answer:

B. 8x^2-6x-7

Step-by-step explanation:

All you have to do is combine the like terms.

Like terms are the terms that have the same variable and same exponent.

The like terms in this equation are 6x^2 and 2x^2, 11x and -17x, and -3 and -4.

When you add 6x^2 and 2x^2, you get 8x^2

When you add 11x and -17x, you get -6x

When you add -3 and -4, you get -7.

Putting these all in order, your answer is

8x^2 - 6x - 7

8 0
3 years ago
5 & 10/13 rounded to the nearest tenth ( A 5.7 B.5.2 C.5 D.4.5)
Black_prince [1.1K]
Hello!

ANSWER:

5 10/13 rounded to the nearest tenth is A) 5.7.
___________________________

EXPLANATION:

Convert 5 10/13 to an improper fraction.

First, multiply the denominator by the whole number:

5 × 13 = 65

Next, add that to the numerator:

65 + 10 = 75

This is the new numerator. Place it over the old denominator.

5 10/13 = 75/13

-------------------------------------------------------

Now, convert the improper fraction to a decimal by dividing its numerator by its denominator:

75 ÷ 13 = 5.7692307692

This can be rounded to 5.7.


3 0
3 years ago
Given the polynomial function
makvit [3.9K]

I think the answer is (x+1)(x-2)(x-3)

8 0
3 years ago
Solve x^2=2x+3 by factoring
solong [7]

The solution is x = 1 and x = -3

<em><u>Solution:</u></em>

Given that we have to solve the given equation by factoring

Given equation is:

x^2=2x + 3\\\\x^2 - 2x - 3 = 0

\text{Consider the form } x^2+bx+c

Find a pair of integers whose product is c and and whose sum is b

\text{Compare } x^2-2x-3 = 0 \text{ with } x^2+bx +c\\\\\text{We get } b = -2 \text{ and } c = -3

Now find, a pair of integers whose sum is -2 and product is -3

The integers that satisfies this condition is -1 and 3

When we add - 1 and 3 we get 2

When multiply -1 and 3 we get -3

Thus the pair of integers are -1 and 3

Write the factored form using these integers.

(x-1)(x+3) = 0

The Zero Product Property states that if ab = 0, then either a = 0 or b = 0, or both a and b are 0

Set the factors equal to 0

x - 1 = 0 \text{ and } x + 3 = 0

x = 1 and x = -3

Thus the solution is x = 1 and x = -3

4 0
3 years ago
Convert the following decimal to a percentege!!!!!! brainlest too
AfilCa [17]

Answer:

8.61%

61.29%

14.86%

20%

Step-by-step explanation:

8 0
3 years ago
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