5 & 10/13 rounded to the nearest tenth ( A 5.7 B.5.2 C.5 D.4.5)

1 answer:

3 0

Hello!

ANSWER:

5 10/13 rounded to the nearest tenth is A) 5.7.
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EXPLANATION:

Convert 5 10/13 to an improper fraction.

First, multiply the denominator by the whole number:

5 × 13 = 65

Next, add that to the numerator:

65 + 10 = 75

This is the new numerator. Place it over the old denominator.

5 10/13 = 75/13

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Now, convert the improper fraction to a decimal by dividing its numerator by its denominator:

75 ÷ 13 = 5.7692307692

This can be rounded to 5.7.

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Mrs taylor gave each of her students 75 pieces paper at the beginning of the school year if there are 32 students in her class h

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Problem
Mrs. Taylor handed out 75 sheets of paper to each student in her class. If she has 32 students, how many total sheets of paper did she hand out?

Result
2,400 sheets of paper

Solution
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3 0

2 years ago

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Determine g(x + a) – g(x) for the following function.<br> g(x) = 5x2 + 2x

dusya [7]

Answer:

$g(x + a) - g(x) = 10ax + 5a^2 + 2a$

Step-by-step explanation:

We are given the function:

$g(x) = 5x^2 + 2x$

And we want to determine:

$\displaystyle g(x+a) - g(x)$

Substitute:

$\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \end{aligned}$

And simplify:

$\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \\ \\ &= \left(5(x^2 + 2ax + a^2) + (2x + 2a) \right) + \left(-5x^2 - 2x\right) \\ \\ &= \left((5x^2 + 10ax + 5a^2) + (2x + 2a)\right) + \left(-5x^2 - 2x\right) \\ \\ &= (5x^2-5x^2) + (10ax + 2x - 2x) + (5a^2+2a) \\ \\ &= 10ax + 5a^2 + 2a \end{aligned}$