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suter [353]
2 years ago
6

the length of the rectangle is measured as 370mm correct to 2 significant figures.a) what is the upper bound for the length?the

width of this rectangle is measured as 19.4mm correct to 1 decimal place.b) what is the lower bound for the area of the rectangle?
Mathematics
1 answer:
ivanzaharov [21]2 years ago
7 0

Answer:

a) 375

b) 7062.75 mm²

Step-by-step explanation:

b) We need to find the shortest possible width and length to get the smallest possible area.

To get the boundaries for 19.4, we go on to the next significant figure (the hundredths) and ± 5 of them.

The boundaries are, therefore: 19.35 - 19.45

As for the length, we can see they've added 5 units as the measurement is correct to 2 sig' figures, which is the tens.

And so, if we do as we did before, we go to the next sig' figure (the units) and ± 5 of them, we get the boundaries to be 365 - 375.

Now, we just multiply the lower bounds of the length and width to get the minimal/lower-bound area:

365 * 19.35 = 7062.75 mm²

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Answer:

figure skates will be $1 cheaper.

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<u>given equation</u>:

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<u>solve for rent of figure skates</u>:

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f(3) = 1.50(3) + 2.00

f(3) = 6.5

<u>solve for rent of hockey skates</u>:

h(x) = 2x + 1.5

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2 years ago
the pattern continues, what would be the eighth number in the pattern?4. 25, 28, 32, 37, 43 ______ PLS HELP ME
fredd [130]

25,28,32,37,43,50,58,67.

\boxed{The\:eighth\:number\:in\:the\:pattern\:is\:67.}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

25, 28, 32, 37, 43,50,58,67\\ ✒ \: 25 + 3 = 28 \\ ✒ \: 28 + 4 = 32 \\ ✒ \: 32 + 5 = 37 \\ ✒ \: 37 + 6 = 43 \\ ✒ \: 43 + 7 = 50 \\ ✒ \: 50 + 8 = 58 \\ ✒ \: 58 + 9 = 67

\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}

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algol13

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Because 19$ 20% off=15.20 and you added taxes]

Have a great day :}

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