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2 years ago

Please help me out on all of these !! Thank you

Mathematics

1 answer:

MakcuM [25]2 years ago

8 0

Answer:

A. $110.00

B. ???

C. $83.00

D. 37 Day's

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PRACTICE ANOTHER A piece of wire 18 m long is cut into two pieces. One piece is bent into a square and the other is bent into an

sergejj [24]

Answer:

Step-by-step explanation:

We have the equations

4x + 3y = 18 where x = the side of the square and y = the side of the triangle

For the areas:

A = x^2 + √3y/2* y/2

A = x^2 + √3y^2/4

From the first equation x = (18 - 3y)/4

So substituting in the area equation:

A = [ (18 - 3y)/4]^2 + √3y^2/4

A = (18 - 3y)^2 / 16 + √3y^2/4

Now for maximum / minimum area the derivative = 0 so we have

A' = 1/16 * 2(18 - 3y) * -3 + 1/4 * 2√3 y = 0

-3/8 (18 - 3y) + √3 y /2 = 0

-27/4 + 9y/8 + √3y /2 = 0

-54 + 9y + 4√3y = 0

y = 54 / 15.93

= 3.39 metres

So x = (18-3(3.39) / 4 = 1.96.

This is a minimum value for x.

So the total length of wire the square for minimum total area is 4 * 1.96

= 7.84 m

There is no maximum area as the equation for the total area is a quadratic with a positive leading coefficient.

3 0

2 years ago

What container would logically hold 1000 liters i need to know in next five minute!!!

valkas [14]

A storage tank. I hope this helps ^^

3 0

3 years ago

The graph of y = 2 is shifted down by 6 units and to the left by 9 units.

luda_lava [24]

Answer:

(-9, -4)

Step-by-step explanation:

7 0

2 years ago

QUADRATIC FORMULA SIMPLIFIED PLZ HELP

olga2289 [7]

Answer:

3x² + 5x + 1 = 0 simplified

x = (-5 ± $\sqrt{13}$ )/6 roots

Step-by-step explanation:

Given quadratic formula

3x² + 5x - 5 = - 6

Standard form

ax² + bx + c = 0

Simplifying

3x² + 5x - 5 + 6 = 0
3x² + 5x + 1 = 0

Solving

x = (-5 ± $\sqrt{5^2 -4*3*1}$ )/(2*3)
x = (-5 ± $\sqrt{13}$ )/6

6 0

2 years ago

Find f(x) and g(x) so that the function can be described as y = f(g(x)). y = 4/x^2+9

dlinn [17]

I'm assuming all of (x^2+9) is in the denominator. If that assumption is correct, then,

One possible answer is $f(x) = \frac{4}{x}, \ \ g(x) = x^2+9$

Another possible answer is $f(x) = \frac{4}{x+9}, \ \ g(x) = x^2$

There are many ways to do this. The idea is that when we have f( g(x) ), we basically replace every x in f(x) with g(x)

So in the first example above, we would have

$f(x) = \frac{4}{x}\\\\f( g(x) ) = \frac{4}{g(x)}\\\\f( g(x) ) = \frac{4}{x^2+9}$

In that third step, g(x) was replaced with x^2+9 since g(x) = x^2+9.

Similar steps will happen with the second example as well (when g(x) = x^2)

4 0

3 years ago