Answer for 80 points. Why some absolute value equations can have a extraneous solution?
1 answer:
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Answer:
7.28 units
Step-by-step explanation:
Using the Pythagorean theorem, , we get:
≈ 7.28
Equation of a line:
m = gradient: The difference between two y points and two x points.
c = y-intercept: Where the line crosses the y-axis (x=0)
You have:
so you are missing the m and the c.
To calculate m find two y coordinates -you have (12, <u>7</u>) and (0, <u>1</u>)- and subtract them. Then divide this by the subtracted values of the x coordinates -you have (<u>12</u>, 7) and (<u>0</u>, 1)- This gives:
To calculate the c, you just see where the line crosses the y-axis. Because you have the point (0, 1), you know that when x=0, y=1. Because x=0 is on the y-axis, you can tell that the line passes through y=1. This makes your c = 1:
When you plug these values into the equation you get your answer:
m = gradient: The difference between two y points and two x points.
c = y-intercept: Where the line crosses the y-axis (x=0)
You have:
so you are missing the m and the c.
To calculate m find two y coordinates -you have (12, <u>7</u>) and (0, <u>1</u>)- and subtract them. Then divide this by the subtracted values of the x coordinates -you have (<u>12</u>, 7) and (<u>0</u>, 1)- This gives:
To calculate the c, you just see where the line crosses the y-axis. Because you have the point (0, 1), you know that when x=0, y=1. Because x=0 is on the y-axis, you can tell that the line passes through y=1. This makes your c = 1:
When you plug these values into the equation you get your answer:
x=-3, y=1
Step-by-step explanation:
Given equations are:
2x-3y=-9 Eqn 1
x+y = - 2 Eqn 2
From eqn 2:
Putting x=-y-2 in eqn 1
Hence,
x=-3, y=1
Keywords: Linear equations, Variables
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