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uranmaximum [27]
3 years ago
11

Please help me fast this is due tomorrow!!

Mathematics
1 answer:
strojnjashka [21]3 years ago
4 0
To find slope it is rise over run which is 20/60 but that can be reduced to 1/3. Do your equation of the line is y=1/3x
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At the airport, there is a moving walkaway 500 meters long, which moves at a speed of 4 km/hour. Aditya and Ravi step on the wal
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He is approximately 166.6 m ahead of Ravi.

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2 years ago
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Consider that ΔQRS is similar to ΔLMN and the measure of ∠N is 42°. What is the measure of ∠S? A) 42° B) 48° C) 56° D) 58°
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3 years ago
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Tess created a Pythagorean triple of (24, 32, 40) by multiplying the known Pythagorean triple 3, 4, and 5 by 8. Is Tess correct?
pentagon [3]

Answer:

(24, 32, 40) is a Pythagorean triplet.

Option A) Yes, as long as each number in the Pythagorean triple is multiplied by the same whole number.                

Step-by-step explanation:

We are given the following in the question:

Pythagorean triplet: (3,4,5)

New Pythagorean triplet obtained = (24, 32, 40)

Pythagoras theorem:

For a right angles triangle the sum of square of sides of triangle is equal to the square of hypotenuse of triangle.

Verification:

24^2 + 32^2\\=576 + 1024\\=1600\\=40^2

Yes, Tessa is correct.

(24, 32, 40) is a Pythagorean triplet.

Pythagorean triple be created using multiplies of a known Pythagorean triple

Option A) Yes, as long as each number in the Pythagorean triple is multiplied by the same whole number.

8 0
3 years ago
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Please help need answers
bogdanovich [222]

see explanation below

(1) \frac{1}{5} × \frac{2}{2} = \frac{2}{10} = 0.2

(2) \frac{6}{25} × \frac{4}{4} = \frac{24}{100} = 0.24

(3) 2 \frac{3}{4} = 2 +\frac{75}{100} = 2.75

(4) 3 \frac{9}{10} = 3 + 0.9 = 3.9

(5) 1.25 = 1 \frac{1}{4} = \frac{5}{4}

(6) 3.29 = 3 \frac{29}{100} = \frac{329}{100}

(7) 0.65 = \frac{65}{100} = \frac{13}{20} in simplest form

(8) 5.6 = 5 \frac{6}{10} = 5 \frac{3}{5} = \frac{28}{5}

(9) he is incorrect

\frac{3}{5} × \frac{20}{20} = \frac{60}{100} = 0.6 ≠ 3.5


7 0
3 years ago
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