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3 years ago

5x + 12 = 2x + 21 Step by step (Right answer plz )

Mathematics

2 answers:

vladimir2022 [97]3 years ago

8 0

Answer:

$5x + 12 = 2x + 21 \\ 5x - 2x = 21 - 12 \\ 3x = 9 \\ x = \frac{9}{3}\\ \boxed{x = 3}$

<u>x = 3</u> is the right answer.

jek_recluse [69]3 years ago

3 0

Answer:

$5x + 12 = 2x + 21 \\ 5x - 2x = 21 - 12 \\ 3x = 9 \\ x = \frac{9}{3} \\ x = 3$

Step-by-step explanation:

please mark me brainliest

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Answer:

55.1724%

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3 years ago

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4 years ago

I need help with this problem 4÷36.2 in long Division

nikitadnepr [17]

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3 years ago

Read 2 more answers

find the area of the isocele triangle formed by the points of intersection of parabolas y=-x^2+9 and y=2x^2-3 and the origin

leonid [27]

Answer:

$10\ \text{sq. units}$

Step-by-step explanation:

The parabola's are

$y=-x^2+9$

$y=2x^2-3$

$-x^2+9=2x^2-3\\\Rightarrow 12=3x^2\\\Rightarrow \\\Rightarrow x=\sqrt{\dfrac{12}{3}}\\\Rightarrow x=\pm 2$

$y=-x^2+9=-(2)^2+9\\\Rightarrow y=5$

$y=-(-2)^2+9=5$

So, the points at which the parabola's intersect each other is $(2,5)$ and $(-2,5)$

The three points of the triangle are $(2,5)$ , $(-2,5)$ and $(0,0)$

Area of a triangle is given by

$A=\dfrac{1}{2}[x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2)]\\\Rightarrow A=\dfrac{1}{2}[2(5-0)+(-2)(0-5)+0(5-5)]\\\Rightarrow A=10\ \text{sq. units}$

Area of the triangle formed is $10\ \text{sq. units}$ .

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3 years ago

Help me work this out I’m having trouble

Alborosie

The variable 'T' equals -20.

6 0

3 years ago