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3 years ago

I need help rally fast this is a test WILL MARK BRAINLEST!!

Mathematics

1 answer:

lawyer [7]3 years ago

7 0

Answer:

3:11

Step-by-step explanation:

8:3 is the ratio because, to make his special energy drink Jerome uses 8 cups of water and 3 cups of drink mix. <u>Becasue, there are a total of 11 cups, and he only uses three cups as the drink mix</u>

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Is the following number an integer?<br> 30/6

tatiyna

Answer:

No, because 30 divided by 6 equals 5, and 5 is a whole number.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

P URGENT I've got a timer going on but really need your help to answer this thank you!!

astraxan [27]

Given:

The radius of inner circle = 13 yd.

The width of the shaded region = 8 yd

To find the area of the shaded region.

Now,

The radius of the outer circle = 13+8 yd = 21 yd

Formula

The area of a circle of radius r unit is $\pi r^{2}$ sq unit.

$A = A_{1}-A_{2}$

where, $A$ = The area of the shaded region

$A_{1}$ = Area of the outer region

$A_{2}$ = Area of the inner region

Now,

$A_{1}$ $=$ $\pi (21^{2})$

$A_{1} = (3.14)(21)(21)$

$A_{1}$ $= 1384.74$ sq yd

And,

$A_{2}$ $=$ $\pi (13^{2})$

$A_{2} = (3.14)(13)(13)$

$A_{2}$ $= 530.66$ sq yd

Therefore,

$A = 1384.74-530.66$ sq yd

$A = 854.08$ sq yd

Hence,

The area of the shaded region 854.08 sq yd.

7 0

3 years ago

4- A manufacturing process produces items whose weights are normally distributed. It is known that 22.57% of all the items produ

galben [10]

Answer:

$\\ \mu = 118\;grams\;and\;\sigma=30\;grams$

Step-by-step explanation:

We need to use z-scores and a standard normal table to find the values that corresponds to the probabilities given, and then to solve a system of equations to find $\\ \mu\;and\;\sigma$ .

<h3>First Case: items from 100 grams to the mean</h3>

For finding probabilities that corresponds to z-scores, we are going to use here a <u>Standard Normal Table </u><u><em>for cumulative probabilities from the mean </em></u><em>(Standard normal table. Cumulative from the mean (0 to Z), 2020, in Wikipedia) </em>that is, the "probability that a statistic is between 0 (the mean) and Z".

A value of a z-score for the probability P(100<x<mean) = 22.57% = 0.2257 corresponds to a value of z-score = 0.6, that is, the value is 0.6 standard deviations from the mean. Since this value is <em>below the mean</em> ("the items produced weigh between 100 grams up to the mean"), then the z-score is negative.

Then

$\\ z = -0.6\;and\;z = \frac{x-\mu}{\sigma}$

$\\ -0.6 = \frac{100-\mu}{\sigma}$ (1)

<h3>Second Case: items from the mean up to 190 grams</h3>

We can apply the same procedure as before. A value of a z-score for the probability P(mean<x<190) = 49.18% = 0.4918 corresponds to a value of z-score = 2.4, which is positive since it is after the mean.

Then

$\\ z =2.4\;and\; z = \frac{x-\mu}{\sigma}$

$\\ 2.4 = \frac{190-\mu}{\sigma}$ (2)

<h3>Solving a system of equations for values of the mean and standard deviation</h3>

Having equations (1) and (2), we can form a system of two equations and two unknowns values:

$\\ -0.6 = \frac{100-\mu}{\sigma}$ (1)

$\\ 2.4 = \frac{190-\mu}{\sigma}$ (2)

Rearranging these two equations:

$\\ -0.6*\sigma = 100-\mu$ (1)

$\\ 2.4*\sigma = 190-\mu$ (2)

To solve this system of equations, we can multiply (1) by -1, and them sum the two resulting equation:

$\\ 0.6*\sigma = -100+\mu$ (1)

$\\ 2.4*\sigma = 190-\mu$ (2)

Summing both equations, we obtain the following equation:

$\\ 3.0*\sigma = 90$

Then

$\\ \sigma = \frac{90}{3.0} = 30$

To find the value of the mean, we need to substitute the value obtained for the standard deviation in equation (2):

$\\ 2.4*30 = 190-\mu$ (2)

$\\ 2.4*30 - 190 = -\mu$

$\\ -2.4*30 + 190 = \mu$

$\\ \mu = 118$

7 0

2 years ago

What is the slope of the line?

koban [17]

4/3 USE THE FORMULA TO GET YOUR ANSWER

5 0

3 years ago

A car is traveling at 20.0 m/s, and the driver sees a traffic light. turn red. After 0.530 s (the reaction time), the driver app

slava [35]

Before the driver applies the brakes ( with the reaction time ):
d 1 = v0 · t = 20 m/s · 0.53 s = 10.6 m
After that:
v = v0 - a · t1
0 = 20 m/s - 7 · t1
7 · t1 = 20
t1 = 2.86 s
d 2 = v 0 · t1 - a · t1² / 2
d 2 = 20 m/s · 2.86 s - 7 m/s² · (2.86 s)²/2 = 57.2 m - 28.6 m = 28.6 m
d = d 1 + d 2 = 10.6 m + 28.6 m = 39.2 m
Answer: the stopping distance of a car is 39.2 m.

5 0

2 years ago