Calculate the mass of a sample of gold that
2 answers:
Answer:
Explanation:
We are asked to calculate the mass of a sample of gold. We are given the density and volume.
Density is a substance's mass per unit volume. Therefore, the formula for calculating density is:
The density is 19.3 grams per cubic centimeter and the volume is 0.242 cubic centimeters. Substitute the values into the formula.
- ρ=19.3 g/cm³
- v= 0.242 cm³
We are solving for the mass of the gold sample, so the variable m must be isolated. It is being divided by 0.242 cubic centimeters. The inverse operation of division is multiplication. Multiply both sides of the equation by 0.242 cm³.
The units of cubic centimeters cancel.
The original measurements of mass and density both have 3 significant figures, so our answer must have the same. For this number, 3 sig fig is the hundredth place. The 0 in the thousandth place tells us to leave the 7.
The mass of the gold sample is approximately <u>4.67 grams.</u>
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The given question is incomplete. The complete question is :
Welding is an industrial process that is used to join pieces of metal. A certain mixture of gases used in welding is composed of carbon dioxide and argon. The partial pressure of carbon dioxide is 0.080 atm and the partial pressure of argon is 0.24 atm. What is the total pressure of the mixture.
Answer: 0.32 atm
Explanation:
According to Dalton's law, the total pressure is the sum of individual pressures.
Given : =total pressure of gases = ?
= partial pressure of carbon dioxide = 0.080 atm
= partial pressure of argon = 0.24 atm
putting in the values we get:
Thus the total pressure of the gases is 0.32 atm
<span>Molar mass (MM) of benzene C6H6
C = 6 * 12 = 72u
H = 6 * 1 = 6u
MM C6H6 = 72 + 6 = 78 g / mol
Benzene - Molar Mass = 78 g --------- 1 mol
Of A Mix has 468 g -------------- x
78x = 468
X = 468/78
X = 6 moles
Molar mass (MM) of Hydrochloric Acid HCl H = 1 * 1 = 1u
CI = 1 * 35 = 35u
MM HCl = 1 + 35 = 36 g / mol
Hydrochloric Acid - Molar Mass = 36 g ---------- 1 mol
Of A Mix has 72 g ------------ y
36y = 72
Y = 72/36
Y = 2 moles
Thus, a mixture has a total of 8 moles (6 mol + 2 mol).
Dividing One Mole Amount of Each Substance by the Number of Total Mole Amounts, Then we will obtain a Molar Fraction of Each:
Molar fraction make benzene = (6/8) simplify 2 = 3/4
Molar Fraction to make Hydrochloric Acid = (2/8) = simplify 2 = 1/4
Note:. The sum of the molar fractions of the always give goes 1, we have: 3/4 + 1/4 = 1
ANSWER:
</span>
C = 6 * 12 = 72u
H = 6 * 1 = 6u
MM C6H6 = 72 + 6 = 78 g / mol
Benzene - Molar Mass = 78 g --------- 1 mol
Of A Mix has 468 g -------------- x
78x = 468
X = 468/78
X = 6 moles
Molar mass (MM) of Hydrochloric Acid HCl H = 1 * 1 = 1u
CI = 1 * 35 = 35u
MM HCl = 1 + 35 = 36 g / mol
Hydrochloric Acid - Molar Mass = 36 g ---------- 1 mol
Of A Mix has 72 g ------------ y
36y = 72
Y = 72/36
Y = 2 moles
Thus, a mixture has a total of 8 moles (6 mol + 2 mol).
Dividing One Mole Amount of Each Substance by the Number of Total Mole Amounts, Then we will obtain a Molar Fraction of Each:
Molar fraction make benzene = (6/8) simplify 2 = 3/4
Molar Fraction to make Hydrochloric Acid = (2/8) = simplify 2 = 1/4
Note:. The sum of the molar fractions of the always give goes 1, we have: 3/4 + 1/4 = 1
ANSWER:
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Answer:inner Diameter =9.19cm
Explanation:
Density is calculated as Mass/ Volume
therefore
Volume= Mass/ Density = 1360g/ 0.953g/ml=1,427 ml
1ml = 1cm³
1,427ml = 1,427cm³
Also We know that Volume of a cylinder = πr²h or πr²l
1,427cm³ = 3.142 x r² x 21.5 cm
r² = 1,427cm³/ (3.142 x 21.5cm)
r² =21.124cm²
= r²
r= 4.596cm
Diameter= 2 x radius
=2 x 4.596
=9.19cm