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Anuta_ua [19.1K]
3 years ago
6

6. What is the total number of calories lost when 10

Chemistry
1 answer:
Nadusha1986 [10]3 years ago
3 0

Answer:

B

Explanation:

so you started out with 80

you have to cool it till 60

so it is decreasing which means you have to subtract

Note=if something is increasing or wanting to go up its addition but for this problem 60 is less then 80 so we are doing subtraction

80-60=20

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A balloon contains 0.218mol of gas and has volume of 4.8 L. If an additional 0.075 mil of gas is added to the ballon, what is th
wariber [46]

Answer:

1. 6.45 L

2. 1.76 x 10²³ molecules

Explanation:

1. Avagadros law states that volume of gas at constant temperature and pressure is directly proportional to the amount / number of moles of that gas

we can use the following equation

v1/n1 = v2/n2

where v1 is volume and n1 is number of moles at first instance

and v2 is volume and n2 is number of moles at second instance

at the first instance - n1 = 0.218 mol

second instance - n2  = 0.218 mol + 0.075 mol  = 0.293 mol

substituting the values

4.8 L / 0.218 mol = v2 / 0.293 mol

v2 = 6.45 L

new volume is 6.45 L

2. 1 mol of any substance is made of 6.022 x 10²³ units. These units could be atoms making up elements or molecules making up a compound.

therefore if 1 mol consists of 6.022 x 10²³  molecules

then 0.293 mol consists of - 6.022 x 10²³ molecules/mol x 0.293 mol = 1.76 x 10²³ molecules

therefore there are 1.76 x 10²³ molecules now in the cylinder

8 0
3 years ago
How do I solve this?? ok having a hard time BRAINLIST​
USPshnik [31]

Answer:

1) 6(1/2)

2) 8(4/5)

Explanation:

1) 7 - 1/2 = 7/1 - 1/2 = 14/2 - 1/2 = 13/2 = 6(1/2)

2) 11(2/5) - 2(3/5) = 57/5 - 13/5 = 44/5 = 8(4/5)

8 0
3 years ago
A sample of air has a volume of 140 mL 0.980 atm. At what pressure will its final volume be 50.0 mL at constant temperature?
bogdanovich [222]

Answer:

The new pressure is 2, 74 atm

Explanation:

We apply Boyle Mariotte's law, where for a given mass of gas at constant temperature, the pressure and volume vary inversely proportionally:        P1xV1 = P2xV2  P2=( P1 x V1)/V2     1 L-----1000L--->( 140ml/1000ml)x1L=0,140 L

(50ml/1000ml)x 1L =0,050L

P2= (0,980 atm x 0,140 L)/0,050L= 2, 744 atm

4 0
3 years ago
1234567 sc: thatbitxh.lizzy
sesenic [268]

Answer:

okyay

Explanation:

lol

8 0
3 years ago
Read 2 more answers
How many seconds does it take to deposit 0.94 g of Ni on a decorative drawer handle when 14.9 A is passed through a Ni(NO3)2 sol
Goshia [24]

Answer:

Time take to deposit Ni is 259.02 sec.

Explanation:

Given:

Current I = 14.9 A

Faraday constant = 96485 \frac{C}{mole}

Molar mass of Ni = 58.69 \frac{g}{mole}

Mass of Ni = 0.94 g

First find the no. moles in Ni solution,

Moles of Ni = \frac{0.94}{58.69}

                   = 0.02 mol

From the below reaction,

  Ni^{2+}  + 2e ⇆ Ni_{(s)}

Above reaction shows "1 mol of Ni^{2+} requires 2 mol of electron to form 1 mol of Ni_{(s)} "

So for finding charge flow in this reaction we write,

    = 0.02 \times \frac{2  }{1 }  \times 96485 \frac{C}{mol}

Charge flow = 3859.4 C

For finding time of reaction,

  I = \frac{q}{t}

Where q = charge flow

   t = \frac{q}{I}

   t = \frac{3859.4}{14.9}

   t = 259.02 sec

Therefore, time take to deposit Ni is 259.02 sec.

3 0
3 years ago
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