Answer:
Kc = 0.023
Explanation:
The detailed steps to determine the equilibrium constant in terms of concentration is as shown in the attachment.
Answer: nS²
Answer: According to the periodic law, elements that fall into the same group have similar properties.
All the alkaline earth metals are in group two of the periodic table. The have 2 electrons in their outermost shell. In the SPDF electronic configuration the ground state of all alkaline earth have S² two electrons in their outermost S sublevel.
Example the electronic configuration of some alkaline earth metals are
Beryllium [He] 2S²
Magnesium is [Ne] 3S² and
Calcium is [Ar] 4S²
the general electronic configuration for alkaline earth metals is nS²
Hello,
An answer is the group of reactive nonmetals and Noble gases.
I am not sure what the colored boxes mean, referring to my periodic table. However, the nonmetals are Hydrogen, Carbon, Nitrogen, etc., including the Noble gases.
Green and purple below, then hydrogen of course.
The vapour pressure of a substance actually differs
relative to the temperature. So to know which compound has the vapour pressure
of 58 kilopascals at 65 degrees Celsius, we refer to standard tables of
temperature vs Vapour pressure.
From the tables or graph, the answer here is:
<span>2. ethanol</span>
Answer:
(A) 0.80 M
(B) 0.64 g
(C) 0.050 M
(D) 1.6 M
Explanation:
(A)
Convert 4.0 g to moles with molar mass. Convert 125 mL to L.
4.0 g x (1 mol/39.998 g) = 0.100 mol
125 mL x (1 L/1000 mL) = 0.125 L
Molarity = mol/L
Molarity = 0.100 mol/0.125 L = 0.80 M
(B)
Find moles of NaOH with the molarity you just found. And convert 20 mL to L.
Molarity = mol/L
0.80 M = mol/0.020 L
mol = 0.016
Convert moles to grams with molar mass.
0.016 mol x (39.998 g/1 mol) = 0.64 g
(C)
You know the molarity of a NaOH solution (Part A). 30 mL initial volume and 480 mL final volume are given. Dilution question so use the dilution formula.
M1V1 = M2V2
(0.80 M)(30 mL) = (M2)(480 mL)
M2 = 0.050 M
(D)
Dilution question again, use the dilution formula.
M1V1 = M2V2
(0.80 M)(200 mL) = (M2)(100 mL)
M2 = 1.6 M