Answer:
The population of a Texas City in 1,995 was 
Step-by-step explanation:
we have
we know that
The population in 1,995 is for 
so
substitute the value of in the function f(x)
Given:
Parent function:
g(x) = (x-h)^2 + k
f(x) = x^2
The vertex of the function g(x) is at (9, -8)
The values of h and k is the value of x and y in the vertex's coordinates which are 9 and -8, respectively
V (h, k)
h = 9
k = -8
g(x) = (x-9)^2 - 8
D + q = 110......d = 110 - q
0.10d + 0.25q = 20.30
0.10(110 - q) + 0.25q = 20.30
11 - 0.10q + 0.25q = 20.30
-0.10q + 0.25q = 20.30 - 11
0.15q = 9.30
q = 9.30/0.15
q = 62 <==== there are 62 quarters
d = 110 - q
d = 110 - 62
d = 48 <==== there are 48 dimes
B. You need to add 73 and 73
Q - 756 = 612 |add 756 to both sides
Q - 756 + 756 = 612 + 756
Q = 1368
