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soldier1979 [14.2K]
3 years ago
13

The value of 110 coins, consisting of dimes and quarters, is $20.30. how many of each kind of coin are there?

Mathematics
1 answer:
deff fn [24]3 years ago
6 0
D + q = 110......d = 110 - q
0.10d + 0.25q = 20.30

0.10(110 - q) + 0.25q = 20.30
11 - 0.10q + 0.25q = 20.30
-0.10q + 0.25q = 20.30 - 11
0.15q = 9.30
q = 9.30/0.15
q = 62 <==== there are 62 quarters

d = 110 - q
d = 110 - 62
d = 48 <==== there are 48 dimes

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Step-by-step explanation:


Total number of tiles: 6+8+6=20

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Probability of getting red in one draw:  \frac{6}{20}=0.3

<em>This means that you would expect to get red 0.3  or 30% of the times.</em>

<em>Hence, when you draw tiles 30 times from the bag, you would expect red to be picked 30% of 30 times. This is:</em>

<em>0.3*30=9</em>

So, you would expect to draw a red tile from the bag 9 times.

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Step-by-step explanation:

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Step-by-step explanation:

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So, we can think of our numbers as

\begin{array}{c|c}x&x\mod 3\\0&0\\1&1\\2&2\\3&0\\4&1\\5&2\\6&0\\7&1\\8&2\\9&0\end{array}

In order to make sure that the sum of any three adjacent numbers is divisible by 3, we have to make sure that any group of 3 three adjacent numbers contains a 0, a 1 and a 2. This is possible only if we arrange our 9 numbers in 3 groups of 3 numbers containing 0,1 and 2 exactly once, repeating always the same pattern.

For example, we could arrange our numbers following the pattern

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216\cdot 6 = 1296

possible arrangements.

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3 years ago
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