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3 years ago

The value of 110 coins, consisting of dimes and quarters, is $20.30. how many of each kind of coin are there?

1 answer:

6 0

D + q = 110......d = 110 - q
0.10d + 0.25q = 20.30

0.10(110 - q) + 0.25q = 20.30
11 - 0.10q + 0.25q = 20.30
-0.10q + 0.25q = 20.30 - 11
0.15q = 9.30
q = 9.30/0.15
q = 62 <==== there are 62 quarters

d = 110 - q
d = 110 - 62
d = 48 <==== there are 48 dimes

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Step-by-step explanation:

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We see that , from the parameterised equation , $r_i^2+r_k^2=s^2sin^24t+s^2cos^24t\\r_i^2+r_k^2=s^2\\r_i^2+r_k^2=r_j$

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By fixing the value of z=0,

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By fixing the value of x=0,

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Thus by fixing the values of x and z alternatively , we get a CIRCULAR PARABOLOID.

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3 years ago

Please help ill mark brainliest

posledela

Answer:

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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