Ask question

Ask question

All categories

4 years ago

14

A red, a green, and a pink backpack are hanging in hobooks in the classroom. The total weigh of the three backpack is 32 pounds.

The red ine weighs 9-3/4 pounds. The green in his one weighs 1-3/4 pounds more than the red one. How much does the pink ne weigh

2 answers:

Artyom0805 [142]4 years ago

5 0

I think it's 20-1/2 hopes it's right

creativ13 [48]4 years ago

3 0

The pink one weighs 20 pounds hopefully its right :)

You might be interested in

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Molodets [167]

Add the following polynomials:
All polynomials are already ordered according to their degree (exponent), and therefore you can just add straight down in columns.
For x3: 2 + 1 - 3 = 0
For x2: -4 + 6 + 2 = 4
For x: 6 - 8 -4 = -6
Constants: -3 + 12 - 7 = 2

The answer is:
4x^2 - 6x + 2

6 0

3 years ago

Which of the following is a main economic variable that affects business cycles?

Natalija [7]

<span>C. Interest rates could be an economic variable that affect business cycles. </span>

6 0

3 years ago

Read 2 more answers

Help me please!!!!!!

Leto [7]

Answer:

2:60

3:480.

sorry I am not able to solve the 6

8 0

3 years ago

If sin theta = 2/3 and sex theta < 0 , find cos theta and tan theta

FromTheMoon [43]

Answer:

$\displaystyle cos\theta=-\frac{\sqrt{5}}{3}$

$\displaystyle tan\theta=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

<u>Trigonometric Formulas</u>

To solve this problem, we must recall some basic relations and concepts.

The main trigonometric identity relates the sine to the cosine:

$sin^2\theta+cos^2\theta=1$

The tangent can be found by

$\displaystyle tan\theta=\frac{sin\theta}{cos\theta}$

The cosine and the secant are related by

$\displaystyle cos\theta=\frac{1}{sec\theta}$

They both have the same sign.

The sine is positive in the first and second quadrants, the cosine is positive in the first and fourth quadrants.

The sine is negative in the third and fourth quadrants, the cosine is negative in the second and third quadrants.

We are given

$\displaystyle sin\theta=\frac{2}{3}$

Find the cosine by solving

$sin^2\theta+cos^2\theta=1$

$\displaystyle \left(\frac{2}{3}\right)^2+cos^2\theta=1$

$\displaystyle cos^2\theta=1-\left(\frac{2}{3}\right)^2=1-\frac{4}{9}=\frac{5}{9}$

$\displaystyle cos\theta=\sqrt{\frac{5}{9}}=-\frac{\sqrt{5}}{3}$

$\boxed{\displaystyle cos\theta=-\frac{\sqrt{5}}{3}}$

We have placed the negative sign because we know the secant ('sex') is negative and they both have the same sign.

Now compute the tangent

$\displaystyle tan\theta=\frac{sin\theta}{cos\theta}=\frac{\frac{2}{3}}{-\frac{\sqrt{5}}{3}}=-\frac{2}{\sqrt{5}}$

Rationalizing

$\displaystyle tan\theta=-\frac{2}{\sqrt{5}}=-\frac{2\sqrt{5}}{5}$

$\boxed{\displaystyle tan\theta=-\frac{2\sqrt{5}}{5}}$

5 0

4 years ago

Which ordered pair would form a proportional relationship with the point graphed below?

kvasek [131]

Answer:

$(x,y) = (-30,10)$

Step-by-step explanation:

Given

$(x,y) = (60,-20)$

Required:

Determine a pair with a proportional relationship

A proportional relationship is:

$k = \frac{y}{x}$

Where k is the constant of proportionality.

$(x,y) = (60,-20)$

So, we have:

$k = \frac{-20}{60}$

$k = -\frac{1}{3}$

This means that for a pair to have a proportional relation, k must be -1/3.

This is true for (c).

Where:

$(x,y) = (-30,10)$

So, we have:

$k = \frac{10}{-30}$

$k = -\frac{1}{3}$

4 0

3 years ago