Answer:
its A
Step-by-step explanation:
A
Answer:
About 1.85 seconds and 13.15 seconds.
Step-by-step explanation:
The height (in feet) of the rocket <em>t</em> seconds after launch is given by the equation:
And we want to determine how many seconds after launch will be rocket be 390 feet above the ground.
Thus, let <em>h</em> = 390 and solve for <em>t: </em>
<em />
<em />
Isolate:
Simplify:
We can use the quadratic formula:
In this case, <em>a</em> = 8, <em>b</em> = -120, and <em>c</em> = 195. Hence:
Evaluate:
Simplify:
Thus, our two solutions are:
Hence, the rocket will be 390 feet above the ground after about 1.85 seconds and again after about 13.15 seconds.
Answer:
C 1055 04 cm
Step-by-step explanation:
We don't need to see the figure, since we know for sure the cone fits into the cylinder (smaller diameter and height).
So, we first need to calculate the volume of the cylinder, which is given by the formula:
VT = π * r² * h
VT = 3.14 * 5² * 16 = 3.14 * 400 = 1,256 cubic cm
Then we calculate the volume of the cone, which is given by:
VC = (π * r² * h)/3
VC = (3.14 * 4² * 12)/3 = (3.14 * 192)/3 = 200.96 cu cm
Then we calculate the void space left inside the cylinder by subtracting the volume of the cone from the volume of the cylinder:
NV = VT - VC = 1,256 - 200.96 = 1,055.04 cu cm
Answer:
the solution os 3p+2≥-10 is p≥-4
Step-by-step explanation:
So.... 3p+2≥-10
<u> -2 -2</u>
3p≥-12
and then you divide...... 3p≥-12
<u>3 3</u>
p≥-4
Answer:
5
Step-by-step explanation:
The answer is 5 because it just is
