Answer:
![\boxed{y = -\dfrac{1}{2}x-6}}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%3D%20-%5Cdfrac%7B1%7D%7B2%7Dx-6%7D%7D)
Step-by-step explanation:
The equation for a straight line is
y = mx + b
where m is the slope of the line and b is the y-intercept.
The line passes through the points (-12, 0) and (0, 6)
(a) Calculate the slope of the line
![\begin{array}{rcl}m & =&\dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\ & = &\dfrac{6 - 0 }{0 - (-12)}\\\\& = &\dfrac{6}{-12}\\\\& = & -\dfrac{1}{2}\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7Dm%20%26%20%3D%26%5Cdfrac%7By_%7B2%7D%20-%20y_%7B1%7D%7D%7Bx_%7B2%7D%20-%20x_%7B1%7D%7D%5C%5C%5C%5C%20%26%20%3D%20%26%5Cdfrac%7B6%20-%200%20%7D%7B0%20-%20%28-12%29%7D%5C%5C%5C%5C%26%20%3D%20%26%5Cdfrac%7B6%7D%7B-12%7D%5C%5C%5C%5C%26%20%3D%20%26%20-%5Cdfrac%7B1%7D%7B2%7D%5C%5C%5Cend%7Barray%7D)
(b) Write the equation
The y-intercept is at x = -6.
![\text{The equation for the line is $\boxed{\mathbf{y = -\dfrac{1}{2}x-6}}$}](https://tex.z-dn.net/?f=%5Ctext%7BThe%20equation%20for%20the%20line%20is%20%24%5Cboxed%7B%5Cmathbf%7By%20%3D%20-%5Cdfrac%7B1%7D%7B2%7Dx-6%7D%7D%24%7D)
The diagram shows the graph of the line passing through the two intercepts.
The present value of a perpetual bond is = annual coupon payment/discount rate
The discount rate = yield = 20% =0.2
Annual coupon payment =$100
Present value of the bond = 100/0.2 = 500
So the present value of the bond is the value that you would end up paying for the bond.
Hence you would pay $500.00 for a bond that pays an annual perpetual coupon of $100 with a yield of 20%
Answer:
a. 3
b. 12
c. In. and "
d. ft. and '
Step-by-step explanation:
c. 13in. or 13"
d. 13ft. or 13'
If you use the property of substitution, you can get (-2, 6.5) as your answer. Substitute the value of X (-2) in the initial equation and solve for Y.
Y= -3/4 (-2) +5 ( I am sure you inadvertently put the Y here also)
Y= 6/4 + 5
Y = 6.5