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3 years ago

Simplify the following expression completely using distribution and combining like terms

Mathematics

2 answers:

Makovka662 [10]3 years ago

7 0

Answer:

-2m - 10

Step-by-step explanation:

3m - 2(5 + 3m) + m =

3m - 10 - 6m + m =

-2m - 10

bezimeni [28]3 years ago

7 0

The answer is -2m -10

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Math help please!?!?!?!??!

mrs_skeptik [129]

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-1a^2b / 2 = 5a^4b/ - 10a^2

2.
3a/b^2 = 3a^4 / 1a^3 b^2

3.
-1/2b = -4a / 8ab

4.
3b^2/1a^2 = -9b^3 / -3a^2b

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3 years ago

In a certain town there were 243 robberies last year. This year the number of robberies has gone down 28%. How many robberies we

VladimirAG [237]

Answer: 175 robberies

Step-by-step explanation:

Robberies last year= 243

Robberies has reduced by 28% which means there are (100-28)% = 72% robberies this year.

Number of robberies this year= 72% of 243 = 72/100 × 243 = 174.96 = 175.

There are 175 robberies this year

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3 years ago

Read 2 more answers

Im give 15 points if you know this phm

pickupchik [31]

Answer:

The answer is option (D) 8.17 × 10^8...

Hope u like it

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3 years ago

A man is 8x years old now .how old he will be in 10 years time

ira [324]

Answer:

He will be 8x+10 years old

Step-by-step explanation:

8x plus 10 = 8x+10

7 0

1 year ago

Determine whether each of the following functions is a solution of laplace's equation uxx uyy = 0.

ratelena [41]

Both functions are the solution to the given Laplace solution.

Given Laplace's equation: $u_{x x}+u_{y y}=0$

We must determine whether a given function is the solution to a given Laplace equation.
If a function is a solution to a given Laplace's equation, it satisfies the solution.

(1) $u=e^{-x} \cos y-e^{-y} \cos x$

Differentiate with respect to x as follows:

$u_x=-e^{-x} \cos y+e^{-y} \sin x\\u_{x x}=e^{-x} \cos y+e^{-y} \cos x$

Differentiate with respect to y as follows:

$u_{x x}=e^{-x} \cos y+e^{-y} \cos x\\u_{y y}=-e^{-x} \cos y-e^{-y} \cos x$

Supplement the values in the given Laplace equation.

$e^{-x} \cos y+e^{-y} \cos x-e^{-x} \cos y-e^{-y} \cos x=0$

The given function in this case is the solution to the given Laplace equation.

(2) $u=\sin x \cosh y+\cos x \sinh y$

Differentiate with respect to x as follows:

$u_x=\cos x \cosh y-\sin x \sinh y\\u_{x x}=-\sin x \cosh y-\cos x \sinh y$

Differentiate with respect to y as follows:

$u_y=\sin x \sinh y+\cos x \cosh y\\u_{y y}=\sin x \cosh y+\cos x \sinh y$

Substitute the values to obtain:

$-\sin x \cosh y-\cos x \sinh y+\sin x \cosh y+\cos x \sinh y=0$
The given function in this case is the solution to the given Laplace equation.

Therefore, both functions are the solution to the given Laplace solution.

Know more about Laplace's equation here:

brainly.com/question/14040033

#SPJ4

The correct question is given below:
Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u = e^(−x) cos(y) − e^(−y) cos(x) u = sin(x) cosh(y) + cos(x) sinh(y)

6 0

2 years ago