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astra-53 [7]
3 years ago
10

A student created a ball and stick molecule during the lesson on molecules and atoms. Examine the model shown here. Which statem

ents can be supported by the information in the model. Select All that apply.

Chemistry
1 answer:
Rzqust [24]3 years ago
4 0

A molecular model is a three dimensional representation of a molecule. It shows all the atoms in the molecule.

The statements that can be supported by the information in the model are;

  • The model shows a molecule with 14 atoms
  • The model shows a molecule with two different elements

We can see from the model shown that there are white balls and black balls. Each ball represents an atom of an element.

There are 14 balls in total meaning that there are 14 atoms presents. Each color of balls stands for an element. There are two different colors in the model implying that there are two different kinds of elements in the molecule.

Learn more: brainly.com/question/156574

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How many moles of air are necessary for the combustion of 5.00 molmol of isooctane, assuming that air is 21.0% O2O2 by volume?
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Answer:

67.5 moles of O2

Explanation:

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8 0
4 years ago
The PH of a solution of Hcl is 2.find out the amount of acid present in a litre of the solution ​
Scrat [10]

Answer:

The solution is 10^-2 or 0.01M in HCl.

Explanation:

meaning of pH is "power of hydrogen".

what is the molar concentration of a HCl solution with pH=2?

Let say pH=2

[H+]=10^-2M

HCL is a strong acid that dissociates completely:

[H+]=[HCL]

Therefore solution is 10^-2 or 0.01M in HCL.

5 0
3 years ago
Which in the following best describe carbon
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4 0
3 years ago
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The following reaction has Kp = 109 at 25°C. 2 NO(g) + Br2(g) equilibrium reaction arrow 2 NOBr(g) If the equilibrium partial pr
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<u>Answer:</u> The equilibrium partial pressure of NO is 0.0034 atm

<u>Explanation:</u>

For the given chemical equation:

NO(g)+Br_2(g)\rightleftharpoons 2NOBr(g)

The expression of K_p for above equation follows:

K_p=\frac{(p_{NOBr})^2}{p_{NO}\times p_{Br_2}}

We are given:

Equilibrium partial pressure of Br_2 = 0.0159 atm

Equilibrium partial pressure of NOBr = 0.0768 atm

K_p=109

Putting values in above equation, we get:

109=\frac{(0.0768)^2}{p_{NO}\times 0.0159}\\\\p_{NO}=0.0034atm

Hence, the equilibrium partial pressure of NO is 0.0034 atm

3 0
3 years ago
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