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3 years ago

What would be the best technique to separate an insoluble solid from a liquid, like sand from water?

Chemistry

2 answers:

german3 years ago

7 0

Answer:

FILTRATION

Explanation:

This is a very simple process with a very simple solution

kogti [31]3 years ago

6 0

Filtration. Filtration is good for separating an insoluble solid from a liquid. (An insoluble substance is one that does not dissolve). Sand, for example, can be separated from a mixture of sand and water using filtration.

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Does ccl4 has resonance structures

krek1111 [17]

Answer:

No, CCl₄ is 4 covalent C-Cl single bonds with a Tetrahedral geometry.

Explanation:l

For resonance structures to exist the molecule must have alternating single-double bonds. H₂C = CH - CH₃ <=> H₃C - CH = CH₂ resents a simple compound with a resonance structure system. This means that the π-bond electrons are distributed across all carbons in the molecular backbone. I would recommend internet searching for Danial Weeks 'Pushing Electrons' for a comprehensive review of molecular resonance structures. It is a brief, but easy to follow treatment of simple to complex structures containing resonance systems.

Hope this helps. Doc :-)

8 0

2 years ago

If 5.32 mols N2 and 15.8 mols H2 react together, what mass NH3 can be

hodyreva [135]

Answer:

2.87 gram

N2 is the limiting agent

Explanation:

We will find out if there is sufficient N2 and h2 to produce NH3

a) For 2.36 grams of N2

Molar mass of N2 = 28.02

Number of moles of N2 in 2.36 grams = 2.36/28.02

Mass of NH3 = 17.034 g

Now NH3 produced form 2.36 grams of N2 =

2.36/28.02 * 2 * 17.034 = 2.87 g NH3

b) For 1.52 g of H2

NH3 produced = 1.52/2.016 * (2/3) * 17.034 = 8.56

N2 Is not enough to produce 2.87 g of NH3 and also H2 is not enough to make 8.56 g of NH3.

N2 is the limiting agent as it has smaller product mass

3 0

2 years ago

What is the average dose of radiation that most people are exposed to every year not including dental or medical personnel deali

andriy [413]

C. The average dose of radiation that most people are exposed to every year not including dental or medical personnel dealing with X-rays is 2400 u Sv.

X-rays are a form of electromagnetic radiation, similar to visible light used for medical treatment and other forms of x ray inspection.

An X-ray, or, much less commonly, X-radiation, is a penetrating form of high-energy electromagnetic radiation.

The average dose of radiation that most people are exposed to every year not including dental or medical personnel dealing with X-rays is 2400 u Sv or 2.4 m u Sv.

Thus, the average dose of radiation that most people are exposed to every year not including dental or medical personnel dealing with X-rays is 2400 u Sv.

Learn more about x ray here: brainly.com/question/24505239

#SPJ1

4 0

2 years ago

Draw a lewis structure for XZ2 (X has 6 valence electrons, F has 7 valence electrons)

jarptica [38.1K]

Answer:

yhpcfjfkg original ogigoyy chandan

7 0

3 years ago

In a 1.0x10^-4 M solution of HClO(aq), identify the relative molar amounts of these species:HClO, OH-, H3O+, OCl-, H2O

yarga [219]

HClO is a weak acid, which means the ions do not fully dissociate. The hydrolysis reaction for the hypochlorous acid is:

HClO + H2O ⇄ H3O+ +OCl-

Then the equilibrium constant, Ka, of dilute HClO would be:

$K_{a} = \frac{[ H_{3} O^{+} ][O Cl^{-} ]}{HClO}$

Then we do the ICE table. I is for the initial concentration, C for the change and E for the excess.

HClO + H2O ⇄ H3O+ + OCl-
I 1.0x10^-4 0 0
C -x +x +x
E (1.0x10^-4 - x) x x

Substituting the excess (E) concentration to the Ka equation:

$K_{a} = \frac{[x ][x]}{1.0 \ x \ 10^{-4} - x }$

Simplifying the equation would yield a quadratic equation:

$x^{2} + K_{a}x-(1.0 \ x \ 10^{-4}) K_{a}=0$

The Ka for HClO is an experimental data which was determined to be 2.9 x 10^-8. Substitute this to the equation, determine the roots, then you get the value for x, which is the concentration of H3O+ and ClO-. Just use your calculator feature Shift-Solve.

x = 1.688 x 10^-6 M = [H3O+] = [ClO-]

Then, you can determine the conc of [OH-] through pH.

pH = -log {H3O+] = -log [1.688 x 10^-6] = 5.77
pOH = 14 - pH = 14 - 5.77 = 8.23
pOH = 8.23 = -log [OH-]
[OH-] = 5.89 x 10^-9 M

Also, since HClO is (1.0x10^-4 - x), then it's concentration would be:
[HClO] = 1.0x10^-4 - 1.688 x 10^-6 = 9.83 x10^-5 M

Let's summarize all concentrations:
[HClO] = 9.83 x10^-5 M
[OH-] = 5.89 x 10^-9 M
[H3O+] = [ClO-] = 1.688 x 10^-6 M
Since the solution is dilute, H2O is relatively higher in concentration.

Thus in relative amounts, the order would be

H2O >>> HClO > H3O+ = ClO- > OH-

6 0

3 years ago

Read 2 more answers