<h3>
Answer:</h3>
132.03 g
<h3>
Explanation:</h3>
<u>We are given;</u>
- The equation for the reaction as;
Fe₂O₃ + 3CO → 2Fe + 3CO₂
- Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
- Mass of CO as 84 grams
We are required to calculate the mass of CO₂ that will produced.
<h3>Step 1: Calculate the number of moles of CO</h3>
Moles = Mass ÷ Molar mass
Molar mass of CO = 28.01 g/mol
Therefore;
Moles of CO = 84 g ÷ 28.01 g/mol
= 2.9989 moles
= 3.0 moles
<h3>Step 2: Calculate the number of moles of CO₂</h3>
- From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂
- Therefore; the mole ratio of CO to CO₂ is 1 : 1
- Hence; Moles of CO = Moles of CO₂
Moles of CO₂ = 3.0 Moles
But; mass = Moles × molar mass
Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol
= 132.03 g
Hence, the mass of CO₂ produced from the reaction is 132.03 g
The final destination to where some of the electrons go to at the end of cellular respiration would be D. Oxygen. Assuming that this aerobic cellular respiration, the final electron acceptor is that of oxygen.
<h2>The required balanced equation:</h2><h2>
</h2>
Explanation:
• Propane when reacts with oxygen it gives carbon dioxide and water.
- In order to make the equation balanced at both ends of the equation,
Add 4 as a coefficient before on L.H.S (Left Hand Side) of Equation.
• Therefore, the required balanced equation is:
Propane, when added with 5 molecules of Water, yields 3 molecules of Carbon Dioxide and 4 molecules of water, as shown in the below equation -
Answer:
It has hollow bones and jaws.
Explanation:
The cladogram shows that Species C has both hollow bones and Jaws. Species A has hollow bones while species B has Jaws. The cladograms shows that species C has both the characteristics.
