F(x) = x^2/2 + 2x + 1f(x) = 1/2 * (x^2 + 4x) + 1f(x) = 1/2 * (x^2 + 4x + 4) - 1/2 * (4) + 1f(x) = 1/2 * (x + 2)^2 - 1
The vertex is (-2, -1). The axis of symmetry is x = -2. The minimum value is -1. The maximum value is infinity.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
The answers X2 plus 4X -21This is because it’s possible
Answer:
Rhombus
Step-by-step explanation:
The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).
We use the distance formula to find the length of AB.



The length of AD is



The length of BC is:



The length of CD is



Since all sides are congruent the quadrilateral could be a rhombus or a square.
Slope of AB
Slope of BC 
Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus
Answer:
<h2>B. 468</h2>
Step-by-step explanation:
We have

If |r| < 1, then the formula of a sum of an infinite geometric sequence is:

Substitute:
