Stuck at these type of problems. Help?
1 answer:
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Any odd number can be represented with 2n+1 where n is a whole number. Also, since the next consecutive number will be even (2n+1+1), then the next consecutive odd number must be 2n+1+2, or 2n+3. Since consecutive odd numbers are separated by 2, then the previous odd number should be 2n-1. So:
<h3>2n-1+2n+1+2n+3=36</h3><h3>6n+3=36</h3><h3>6n+3-3=36-3</h3><h3>6n/3=33/3</h3><h3>2n=11</h3>Now in order to find three odd consecutive numbers that will sum to 36, you must be able to divide 11 evenly by 2, and have a whole number as a result. This is impossible, so there aren't any 3 odd numbers that will sum to 36.
<h2>HOPE IT HELPS ☺️</h2>Answer:
A.
Step-by-step explanation:
Reference angle = 60°
Opposite =
Hypotenuse = x
Adjacent = y
✔️To find x, apply the trigonometric function SOH:
Sin 60° = Opp/Hyp
(sin 60 = √3/2)
Cross multiply
Divide both sides by 2
Divide both sides by √3
Rationalize
✔️To find y, apply the trigonometric function TOA:
Tan 60° = Opp/Adjacent
(tan 60 = √3)
Cross multiply
Divide both sides by √3
Rationalize