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3 years ago

Find the coordinates of the midpoint of each segment formed by the given points. (-4-4) & (4-4).

Mathematics

2 answers:

3241004551 [841]3 years ago

5 0

Answer:

Midpoint (xM, yM) = (4, 5)

Step-by-step explanation:

nordsb [41]3 years ago

3 0

Answer:

the anwser is (-1,4)x=x1+x2 / 2y=y1+y2 / 2

Step-by-step explanation:

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What is the square root of -1?

Sonja [21]

Answer: i

Step-by-step explanation: the awnser is i just trust me here

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3 years ago

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A marketing research company desires to know the mean consumption of milk per week among males over age 32. A sample of 710 male

nydimaria [60]

Answer:

(4.5, 4.7)

Step-by-step explanation:

Hi!

Lets call X to the consumption of milk per week among males over age 32. X has a normal distribution with mean μ and standard deviation σ.

$X \sim N(\mu, \sigma)$

When you know the population standard deviation σ of X , and the sample mean is $\hat X$ , the variable q has distribution N(0,1):

$q = \frac{\hat X - \mu}{\sigma} \sim N(0,1)$

Then you have:

$P(-k < q$

This defines a C - level confidence interval. For each C the value of k is well known. In this case C = 0.98, then k = 2.326

Then the confidence interval is:

$(4.6 - 2.326*\frac{0.8}{\sqrt{710}}, 4.6 + 2.326*\frac{0.8}{\sqrt{710}})\\ (4.5, 4.7)$

5 0

4 years ago

O points<br> Solve for x. Your answer will be of the form ##°

stellarik [79]

Answer:

x = 59

Step-by-step explanation:

Here, we want to get the value of x

To do this, we use an important arc-angle relationship

we have this as:

x = (36 + 82)/2

x = 59

7 0

3 years ago

The difference of a number and 48 is -18

kolbaska11 [484]

If your question is what the value of the number you started with the answer would be 30. to find it you add 48 to -18 and you get 30.

3 0

3 years ago

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Use mathematical induction to prove the statement is true for all positive integers n. 1^2 + 3^2 + 5^2 + ... + (2n-1)^2 = (n(2n-

Charra [1.4K]

Answer:

The statement is true is for any $n\in \mathbb{N}$ .

Step-by-step explanation:

First, we check the identity for $n = 1$ :

$(2\cdot 1 - 1)^{2} = \frac{2\cdot (2\cdot 1 - 1)\cdot (2\cdot 1 + 1)}{3}$

$1 = \frac{1\cdot 1\cdot 3}{3}$

$1 = 1$

The statement is true for $n = 1$ .

Then, we have to check that identity is true for $n = k+1$ , under the assumption that $n = k$ is true:

$(1^{2}+2^{2}+3^{2}+...+k^{2}) + [2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)}{3} +[2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot [2\cdot (k+1)-1]^{2}}{3} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot (2\cdot k +1)^{2} = (k+1)\cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$(2\cdot k +1)\cdot [k\cdot (2\cdot k -1)+3\cdot (2\cdot k +1)] = (k+1) \cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$k\cdot (2\cdot k - 1)+3\cdot (2\cdot k +1) = (k + 1)\cdot (2\cdot k +3)$

$2\cdot k^{2}+5\cdot k +3 = (k+1)\cdot (2\cdot k + 3)$

$(k+1)\cdot (2\cdot k + 3) = (k+1)\cdot (2\cdot k + 3)$

Therefore, the statement is true for any $n\in \mathbb{N}$ .

4 0

3 years ago