Answer:w=6+t/3/2 squared
Step-by-step explanation:
2 squared w= 6+t/3
w=6+t/3/2 squared
I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,
So,
So,
Hope this helps you!
Step-by-step explanation:
The answer is option b.
Explanation in the pic.
Need any other maths, feel free!!
The distance (d) between two points (x1,y1) and (x2,y2) is given by the formula
d = √ ((X2-X1)2+(Y2-Y1)2)
d = √ (-400--800)2+(300-200)2
d = √ ((400)2+(100)2)
d = √ (160000+10000)
d = √ 170000
The distance between the points is 412.310562561766
The midpoint of two points is given by the formula
Midpoint= ((X1+X2)/2,(Y1+Y2)/2)
Find the x value of the midpoint
Xm=(X1+X2)/2
Xm=(-800+-400)/2=-600
Find the Y value of the midpoint
Ym=(Y1+Y2)/2
Ym=(200+300)/2=250
The midpoint is: (-600,250)
Graphing the two points, midpoint and distance
P1 (-800,200)
P2 (-400,300)
Midpoint (-600,250)
The length of the black line is the distance between the points (412.310562561766)
Answer:
I think it is 1/4x not sure but try it
