Given:f(x)=3x^2+1,G(x)=2x-3,H(x)=x F(-2)= a.13 b.37 c.-11

A club is holding a raffle. Ten thousand

Cloud [144]

First take 10,000 * 2 = 20,000, because each of the 10,000 tickets cost 2 dollars.

3000(1/20000) + 1000(3/20000) + 500(5/20000) + 100(20/10000) = 10500/20000 = .525

Thus, each ticket is worth 52.5 cents.

Hope it helps <3

6 0

3 years ago

Is the relationship between the variables in the table a direct variation, an inverse variation, or neither? If it is a direct o

inn [45]

Answer: neither direct variation nor inverse variation.

Explanation:

1) The relation between two variables, y and x, is a direct variation if and only if the quotient between them, y/x, is constant. This is: y / x = k or, equivalently, y = kx.

Note that if y / x is constant, x / y is also constant.

In a direct variation, when x increases, y increases, and when x decreases, y decreases.

2) The relation between two variables, y and x, is an inverse variation if and only if their product, y×x is constant. This is: y × x = k or, equivalently y = k /x or x = k / y.

In an inverse variation when one of the variables increases the other decreases.

3) Writhe the given table and study whether the conditions for direct or inverse variation are met:

x y y/x y×x

-6 -72 -72/(-6) = 12 (-6)(-72) = 432

-4 -47 -47 / (-4) = 11.75 (-4)(-47) = 188

-3 -36 -36 / (-3) = 12 (-3)(-36) = 108

1 12 12 / 1 = 12 (1)(12) = 12

Conclusions;

a) Since neither y / x nor y×x have the same result for every pair, the relation is neither direct nor inverse.

b) Note that if the third pair were (-4, -48) instead of (-4, -47), y / x would be 12, which make a direct variation. In this case the function that modeled it would be:

y = 12x.

8 0

3 years ago

F $1 \le a \le 10$ and $1 \le b \le 36$, for how many ordered pairs of integers $(a, b)$ is $\sqrt{a + \sqrt{b}}$ an integer?

svetlana [45]

You have such entry data:
$1\ \textless \ a\ \textless \ 10 \\ 1\ \textless \ b\ \textless \ 36$

Consider expression $\sqrt{a+ \sqrt{b} }$ . If this expression becomes an integer, then b=4,9,16,25, because then $\sqrt{b} =$ 2,3,4,5, respectively. In other cases $\sqrt{b}$ is not integer and thus the expression $\sqrt{a+ \sqrt{b} }$ also is not integer.

1. b=4, then $\sqrt{a+ \sqrt{b} }=\sqrt{a+2}$ . Here a=2,7 (in other cases $\sqrt{a+2}$ is not integer). When a=2, $\sqrt{a+2}=\sqrt{2+2}=2$ and when a=7, $\sqrt{a+2}=\sqrt{7+2}=3$ .

2. b=9, then a=6 and $\sqrt{a+ \sqrt{b} }= \sqrt{a+3}=\sqrt{6+3}=3$ .

3. b=16, then a=5 and $\sqrt{a+ \sqrt{b} }= \sqrt{a+4}=\sqrt{5+4}=3$ .

4. b=25, then a=4 and $\sqrt{a+ \sqrt{b} }=\sqrt{a+5}=\sqrt{4+5}=3$ .

Answer: (2,4), (7,4), (6,9), (5,16), (4,25).

3 0

3 years ago

What is the domain of f(x)=3x-4

klemol [59]

Answer:

There are no domains so 0

Step-by-step explanation:

The domain of any function is simply all the possible numbers you can input for x

without violating the rules of math.

we cannot have a negative number for x (its against the laws of math), so the domain would be all non-negative numbers

:) Hoped this helped

6 0

3 years ago

Read 2 more answers

Suppose that 70% of the orders on a particular website are shipped to the person who is making the order and the remaining 30% a

labwork [276]

Answer:

a) P=0.24

b) P=0.31

c) Not independent.

Step-by-step explanation:

Incomplete question.

a) What is the probability that a randomly selected order will be wrapped and sent to another person?

$P(W\&SOP)=P(SOP)*P(W|SOP)=0.30*0.60=0.24$

W: wrapped

SOP: sent to other people

b) What is the probability that a randomly selected order will be gift wrapped?

$P(W)=P(SOP)*P(W|SOP)+P(SR)*P(W|SR)\\\\P(W)=0.3*0.6+0.7*0.1=0.24+0.07=0.31$

SR: sent to the right person

c) Is gift wrapping independent of the destination of the gift? Justify your response statistically.

To prove that they are independent, both of the following conditions must be met:

P(x|y) = P(x), for all values of X and Y.

P(x ∩ y) = P(x) * P(y), for all values of X and Y.

We start for the second condition.

$P(W\cap SR)=0.1\\\\P(W)*P(SR)=0.31*0.7=0.217\\\\\\P(W\cap SR)\neq P(W)*P(SR)$

This condition is not met, so the two variables are not independent.

4 0

3 years ago