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topjm [15]
3 years ago
10

4d³ + 16de² – 20df³?​

Mathematics
1 answer:
timama [110]3 years ago
4 0

Answer:

4d x (d^2 + 4e^2 - 5f^3)

Step-by-step explanation:

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If (-1,4) and (3,-2) are end points of diameter of the circle, then the equation of the circle is
Volgvan

Answer:

If you've more doubts you can ask :)

Step-by-step explanation:

If the centre of a circle is (a, b) and radius r, then the equation of the circle is :

(x - x)^2 + (y-b)^2 = r^2

<em><u>First we will find the centre, (a , b): </u></em>

<em><u /></em>a = \frac{3+(-1)}{2} = \frac{2}{2} = 1\\\\b = \frac{-2 + 4}{2} = \frac{2}{2} = 1<em><u /></em>

<em><u>Find radius:</u></em>

Radius, r = \frac{Diameter}{2}

Diameter is the distance between (-1, 4) and (3, -2)

diameter = \sqrt{(x_2 - x_1)^2 +(y_2-y_1)^2} \\\\

             = \sqrt{(3-(-1)^2 + (-2-4)^2} \\\\=\sqrt{16 + 36}\\\\=\sqrt{52}\\\\=\sqrt{4 \times 13}\\\\=2\sqrt{13}    \ units

Therefore , r = \frac{2 \times \sqrt{13} }{2} = \sqrt{13}  \ units

<em><u>Equation of the circle is :  </u></em>

                                 (x - 1)^2 +(y-1)^2 = 13<em><u></u></em>

4 0
3 years ago
V1/V2=T1/T2. Solve for V1
Ahat [919]
V1=(T1/T2)*V2
In this problem, since you are given no actual numbers, the only thing you can do is multiply V2 over to get V1 alone. Since you can't cancel anything out, you are left with the answer above.
4 0
3 years ago
10
Jlenok [28]

Answer:

False

Step-by-step explanation:

3 0
3 years ago
Isosceles trapezoid ABCD has legs If AB = 6y – 3, BC = 4y – 5, and CD = 7y – 18, find the value of y
castortr0y [4]

Answer:

The value of y is y=15

Step-by-step explanation:

We have:

AB = 6y – 3, BC = 4y – 5, and CD = 7y – 18

We define the isosceles trapezoid as it has two opposites parallel, the two other opposites legs are equal and also the diagonals are equal.

Here AB = CD

6y-3 = 7y-18

Combine the like terms:

18-3 = 7y-6y

15 = y

It means the value of y is  y=15....

4 0
3 years ago
NEED HELPS ASAP WILL GIVE BRAINLIST 100 PTS
hodyreva [135]
Hey there!

\ \ \ \ \ \ \ \ \ \Downarrow \ \Downarrow \Downarrow\ \ \ \ \Downarrow \ \ \  \ \Downarrow&#10;&#10;\\ \\   \left[\begin{array}{ccc}  \left[\begin{array}{ccc}  \left[\begin{array}{ccc}5(4x + 2)/7y\end{array}\right] \end{array}\right] \end{array}\right]

(5)=(term) \\ \\ (sum)=(+) \\ \\ (product)= (x) \ or \ (*) \\ \\ (4)=(coefficient) \\ \\ (quotient) = (divided \ by \ symbol) \\ \\ (factor)=(2) \\ \\ \boxed{\boxed{Hope \ this \ helps}}

 
4 0
3 years ago
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