Answer:
Step-by-step explanation:
m∠1+∠2=180
2x+40+2y+40=180
2x+2y=180-80
2x+2y=100
x+y=50
x=50-y
m∠1=m∠3
2x+40=x+2y
2x-x=2y-40
x=2y-40
2y-40=50-y
2y+y=50+40
3y=90
y=30
x=50-y=50-30=20
m∠1=2x+40=2×20+40=80°
m∠2=2y+40=2×30+40=60+40=100°
m∠3=x+2y=20+2×30=80°
Surface Area of a cylinder 2(π•r²)+(2π•r)•h
So
If the diameter is 8 then the radius is 4. the height is 5.
so you have, 2(3.14•4²)+(2•3.14•4)•5
solve. PEMDAS
Parentheses & Exponents first.
2(3.14•16)+(2•3.14•4)•5
2(50.24)+(6.28•4)•5
2(50.24)+(25.12)•5
Multiplication & Division second (left to right)
100.48+125.6
Add & Subtract (left to right)
226.08cm
Answer:
the second one
Step-by-step explanation:
yo sup??
mid point of circle=centre of circle
let centre be O(3,2)
and the point be P(-4,8) and the other point be Q(x,y)
by mid point formula
-4+x/2=3 and 8+y/2=2
x=10 and y=-4
therefore coordinates of the other point are (10,-4)
Hope this helps.
