The next larger thousandth is 36.994 .
The next smaller thousandth is 36.992 .
Neither of those is any nearer to 36.993
than 36.993 already is.
The last '3' at the end of 36.993 is in the thousandths' place.
There is no more piece of another thousandth after it.
So 36.993 is already on a complete thousandth, and
there's no rounding required.
The formula for the average value of a function is

where b is the upper bound and a is the lower. For us, this formula will be filled in accordingly.

. We will integrate that now:
![\frac{1}{2}[ \frac{2x^3}{3}+3x]](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%5B%20%5Cfrac%7B2x%5E3%7D%7B3%7D%2B3x%5D%20%20)
from 0 to 2. Filling in our upper and lower bounds we have
![\frac{1}{2}[( \frac{2(2^3)}{3}+3(2))-0]](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%5B%28%20%5Cfrac%7B2%282%5E3%29%7D%7B3%7D%2B3%282%29%29-0%5D%20%20)
which simplifies to

and

which is 17/3 or 5.667
Start looking like the standards because y’all starting to look the same
Answer:

Step-by-step explanation:
Given
and 
Required
Which compares them correctly

This is incorrect because 0.63 is greater

This is also incorrect because 0.63 is greater

This is also correct because 0.63 is greater

This is also incorrect because 0.63 is greater
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