A. Product of a constant factor 12 and two-term factor x+3
In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.
Let's start with the first equation.
Cross multiply both sides of the equation.
Subtract 6x on both sides of the equation.
Divide both sides of the equation by -5.
Therefore, the slope of the first equation is 4/5.
Let's now simplify the second equation.
Add x on both sides of the equation.
Divide both sides of the equation by -4.
Therefore, the slope of the second equation is -5/4.
Since the slope of each equation is the negative reciprocal of each other, then the graph of the two equations is perpendicular to each other.
Answer:
x²/25 + y²/9 = 1 or 9x² + 25y² = 225
Step-by-step explanation:
We have two points which is y intercepts (0,-3) and (0,3).
We know that the major axis is 2a and secondary axis is 2b
These two points are vertical top of the ellipse which they give us value of half secondary axis b = 3
The length of major axis is 2a = 10 => a = 10/2 = 5 => a = 5
The equation of the ellipse is:
x²/a² + y²/b² = 1 or b²x² + a²y² = a²b²
When we replace value of a and b we get:
x²/5² + y²/3² = 1 or 3²x² + 5²y² = 5² · 3² and finally
x²/25 + y²/9 = 1 or 9x² + 25y² = 225
God with you!!!
A cosine is just a sine shifted to the left by π/2. A cosine of 4x is shifted to the left by only π/8 because of the factor 4. Sketch them.
The region we're looking for is this sausage-shaped part between the cos and the sin.
The x intercepts are at π/8 for the cosine and π/4 for the sine. The midpoint between them is at (π/8 + π/4)/2 = 3/16π.
The region is point symmetric around the x axis, so the y coordinate of the centroid is 0.
So the centroid is at (3/16π, 0)
I'm assuming, from what you've given me that the question is asking to do this.
15n=647
647 divided by 15 equals 43.13...repeated
Let me know if this is what you are looking for.
