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3 years ago

Please help! Find the midpoint of the line segment joining the points R(-4,3) and S(3,6).

Mathematics

2 answers:

Sauron [17]3 years ago

4 0

The formula to find the mid-point of a line segment give the two end points is:

(

)

Where

is the midpoint and the given points are:

(

)

and

(

)

Substituting the values from the points in the problem gives:

(

−

)

(

−

)

(

−

)

Nostrana [21]3 years ago

3 0

Hopefully this helps you.

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What percent of 202 is 34

julia-pushkina [17]

Answer:

Result: 68.68

68.68 is 202% of 34.

Step-by-step explanation:

202% × 34 = 68.68

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3 years ago

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3 years ago

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Log5 (x squared - 9) = 0

andreev551 [17]

Answer:

$x=3,\:x=-3$

Step-by-step explanation:

Given the equation

$\log _{10}\left(5\right)\left(x^2-9\right)=0$

Divide both sides by $\log _{10}\left(5\right)$

$\frac{\log _{10}\left(5\right)\left(x^2-9\right)}{\log _{10}\left(5\right)}=\frac{0}{\log _{10}\left(5\right)}$

Simplify

$x^2-9=0$

Add 9 to both sides

$x^2-9+9=0+9$

Simplifying

$x^2=9$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{9},\:x=-\sqrt{9}$

$\sqrt{9}\:=3$

$-\sqrt{9}=-3$

Therefore,

$x=3,\:x=-3$

3 0

3 years ago

The graph of an absolute value function contains the points (–3, 5), (0, 2) and (3, 5). Which could be the function represented

Alex73 [517]

The absolute value functions that contains the points are:

f(x) = |x| + 2
f(x) = |-x| + 2

<h3>Which could be the function represented by this graph?</h3>

Here we have the points (-3, 5), (0, 2), and (3, 5). We want to see which ones of the given functions have that points.

To check that, we need to evaluate the functions in the first value of each point and see if the outcome is the second value of the correspondent point.

For example, for the first equation:

f(-3) = |-3| + 2 = 5 so it has the point (-3, 5)
f(0) = |0| + 2 = 2 so it has the point (0, 2)
f(3) = |3| + 2 = 5 so it has the point (3, 5).

The other option that also contains these 3 points is:

f(x) = |-x| + 2

f(-3) = |3| + 2 = 5 so it has the point (-3, 5)
f(0) = |-0| + 2 = 2 so it has the point (0, 2)
f(3) = |-3| + 2 = 5 so it has the point (3, 5).

And all the other options can be trivially discarded (by evaluating them).

So the two correct options are:

f(x) = |x| + 2
f(x) = |-x| + 2

If you want to learn more about absolute value functions:

brainly.com/question/3381225

#SPJ1

4 0

2 years ago

Find the coordinates of point Q that lies along the directed line segment from R(-2, 4) to S(18, -6) and partitions the segment

Varvara68 [4.7K]

Check the picture below

thus then

$\bf \qquad \textit{internal division of a line segment}\\\\
R(-2,4)\qquad S(18,-6)\qquad
ratio1=3\qquad ratio2=7\qquad 3:7\\ \quad \\ \quad \\
\cfrac{RQ}{QS}=\cfrac{ratio1}{ratio2}\implies \cfrac{R}{S}=\cfrac{3}{7}
\implies 7R=3S
\\\\\\
7(-2,4)=3(18,-6)$

$\bf {{ Q=\left(\cfrac{\textit{sum of "x" values}}{ratio1+ratio2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{ratio1+ratio2}\right)}}\\ \quad \\
\qquad thus\qquad \\ \quad \\
Q=\left(\cfrac{(7\cdot -2)+(3\cdot 18)}{3+7}\quad ,\quad \cfrac{(7\cdot 4)+(3\cdot -6)}{3+7}\right)$

8 0

3 years ago

Please help! Find the midpoint of the line segment joining the points ​R(​-4,3​) and ​S(3​,6​).

Please help! Find the midpoint of the line segment joining the points R(-4,3) and S(3,6).