Find the surface area of the pyramid

Mathematics

1 answer:

navik [9.2K]1 year ago

6 0

Area of the square base = (6 ft) × (6 ft) = 36 ft²

Area of each triangular face = 1/2 × (6 ft) × (5 ft) = 15 ft²

Then the surface area of the pyramid is

36 ft² + 4 × (15 ft²) = 96 ft²

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bezimeni [28]

Step-by-step explanation:

Remember that in a linear function of the form $f(x)=mx+b$ , $m$ is the slope and $b$ is the why intercept.

Part A. Since $g(x)=2x+6$ , its slope is 2 and its y-intercept is 6

Now, to find the slope of $f(x)$ we are using the slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

where

$m$ is the slope

$(x_1,y_1)$ are the coordinates of the first point

$(x_2,y_2)$ are the coordinates of the second point

From the table the first point is (-1, -12) and the second point is (0, -6)

Replacing values:

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-6--(12)}{0-(-1)}$

$m=\frac{-6+12}{0+1}$

$m=6$

The slope of f(x) is bigger than the slope of g(x), which means the line represented by f(x) is stepper than the line represented by g(x).

Part B. To find the y-intercept of f(x) we are taking advantage of the fact that the y-intercept of a linear function occurs when x = 0, so we just need to look in the table for the value of f(x) when x = 0. From the table $f(x)=-6$ when $x=0$ ; therefore the y-intercept of $f(x)$ is -6.