Answer:
Which of the following situations can be best represented by the inequality 6x + 15 100?
Step-by-step explanation:
because reasons
It’s acute, equilateral and isosceles
<span>We'll make $10 x and the $20 y.
x + y = 7,200
10x + 20y = 113000
10x + 10y = 72000
10x + 20y = 113000
10y = 41,000
y = 4,100
Substitute y = 4,100
x + y = 7,200
x + 4,100 = 7,200
x = 7,200 - 4,100
x = 3,100
3,100 x $10 tickets
4,100 x $20 tickets</span>
1a=3.04
2a=30.4
3a=304
4a=3040
Answer:
the answer to the question is 32
