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Lesechka [4]
3 years ago
9

If you were to workout 6 times a week at the start of the year, how many days would have you worked out at the end of the year?

Mathematics
2 answers:
vova2212 [387]3 years ago
6 0

Answer:

312 days

Step-by-step explanation:

Number weeks per year is 52

Number of days worked out 6x52 = 312 days  

tino4ka555 [31]3 years ago
5 0
No.of weeks in a year=52
Then,accordingly 52*6=312 days
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Look at the screen shot and please help this is my homework please help
Musya8 [376]

Answer:

the unit rate is $4

Step-by-step explanation:

If you divided 36 by nine you get 4

7 0
3 years ago
2 8 −10−15÷3=2, start superscript, 8, end superscript, minus, 10, minus, 15, divided by, 3, equals
Sergio039 [100]

Answer:

241

Step-by-step explanation:

Given the equation to evaluate :

2^8 −10−15÷3

2^8 = 256

256 - 10 - 15 ÷ 3

From BODMAS principle, we evaluate the divison before subtraction :

-15 ÷ 3 = - 5

256 - 10 -5

256 - 15

= 241

8 0
2 years ago
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5 0
3 years ago
The school that Trevon goes to selling tickets to the annual dance competition. On the first day of tickets sales the school sol
KiRa [710]

Answer:

  both kinds of tickets are $5 each

Step-by-step explanation:

Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:

  12s + 5c = 85 . . . . . revenue from the first day of sales

  6s + 9c = 75 . . . . . . revenue from the second day of sales

Double the second equation and subtract the first to eliminate the s variable.

  2(6s +9c) -(12s +5c) = 2(75) -(85)

  13c = 65 . . . . . simplify

  65/13 = c = 5 . . . . . divide by the coefficient of c

Substitute this value into either equation. Let's use the second one.

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  6s = 30 . . . . . . . subtract 45

  30/6 = s = 5 . . . divide by the coefficient of s

The price of a senior ticket is $5; the price of a child ticket is $5.

5 0
3 years ago
Which of the following do you use to tell whether a relationship is<br> proportional or not?
Setler79 [48]

Answer:

The correct option to tell whether a relationship is proportional or not is;

\dfrac{y}{x}

Step-by-step explanation:

A proportional relationship is a relationship between two variables, 'x', and 'y' such that they have equivalent ratio, such that all values of variable 'y' are given by the product of the values of the variable 'x' and a constant, 'k'

Therefore, y = k · x, from which we have;

\dfrac{y}{x} = k = Contant

Therefore we can use \dfrac{y}{x} to tell whether a relationship is proportional or not proportional.

6 0
3 years ago
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