2.02349534E19 is what i got
Answer:
x=10
Step-by-step explanation:
Answer:
hmm
Step-by-step explanation:
If 2 boxes remain empty, it means that we put all three balls in one single box.
Suppose the full box is box number 1. For each ball, we have three choices - we may put it in box number 1, 2 or 3. This means that each box has a 1/3 chance of receiving each ball.
So:
- we choose box 1 for ball 1 - that's a 1/3 chance
- we choose box 1 for ball 2 - that's a 1/3 chance
- we choose box 1 for ball 3 - that's a 1/3 chance
So, the probability of putting all balls in box 1 is
![\dfrac{1}{3}\times\dfrac{1}{3}\times\dfrac{1}{3} = \dfrac{1}{3^3}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B1%7D%7B3%7D%5Ctimes%5Cdfrac%7B1%7D%7B3%7D%5Ctimes%5Cdfrac%7B1%7D%7B3%7D%20%3D%20%5Cdfrac%7B1%7D%7B3%5E3%7D%20)
But this is the probability of putting all ballx in box 1, and you can repeat this logic for box 2 and 3.
So, the probability of putting all balls in one single box is 1/27 for each box, for a total of
![\dfrac{1}{27} \times 3 = \dfrac{1}{9}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B1%7D%7B27%7D%20%5Ctimes%203%20%3D%20%5Cdfrac%7B1%7D%7B9%7D%20)