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Leto [7]
3 years ago
12

10 men who work 9hours per day, complete half of a work in 6days. How many days required for 15 men who work 12 hour per day to

complete the rest of the work ​
Mathematics
1 answer:
S_A_V [24]3 years ago
7 0

Answer:

So, you need 3 days approximately

Step-by-step explanation:

We will use Chain Rule to solve this question.

According to Chain Rule, the work efficiency remains constant.

• WWF×TWWF×T= Constant

• Here W = Work Done, WF = Workforce, T = Time.

Let the number of days  needed be 'x'.

Applying Chain Rule,

10×9×6= 15×12×(x)

Or, x=3x=3 day

So, you need 3 days approximately.

Please mark me brainliest

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On a certain hot​ summer's day, 643 people used the public swimming pool. The daily prices are $1.50 for children and $2.00 for
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249 children and 394 adults swam at the public pool.

Step-by-step explanation:

Number of people swam at pool = 643

Receipts = $1161.50

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Cost for one adult = $2.00

Let,

x be the number of children

y be the number of adults

According to given statement;

x+y=643    Eqn 1

1.50x+2.00y = 1161.50   Eqn 2

Multiplying Eqn 1 by 2

2(x+y=643)\\2x+2y=1286\ \ \ Eqn\ 3\\

Subtracting Eqn 2 from Eqn 3

(2x+2y)-(1.50x+2.00y)=1286-1161.50\\2x+2y-1.50x-2.00y=124.50\\0.5x=124.50

Dividing both sides by 0.5

\frac{0.5x}{0.5}=\frac{124.50}{0.5}\\x=249

Putting x=249 in Eqn 1

249+y=643\\y=643-249\\y=394

249 children and 394 adults swam at the public pool.

Keywords: linear equation, subtraction

Learn more about linear equations at:

  • brainly.com/question/5798698
  • brainly.com/question/5758530

#LearnwithBrainly

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