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Leto [7]
3 years ago
12

10 men who work 9hours per day, complete half of a work in 6days. How many days required for 15 men who work 12 hour per day to

complete the rest of the work ​
Mathematics
1 answer:
S_A_V [24]3 years ago
7 0

Answer:

So, you need 3 days approximately

Step-by-step explanation:

We will use Chain Rule to solve this question.

According to Chain Rule, the work efficiency remains constant.

• WWF×TWWF×T= Constant

• Here W = Work Done, WF = Workforce, T = Time.

Let the number of days  needed be 'x'.

Applying Chain Rule,

10×9×6= 15×12×(x)

Or, x=3x=3 day

So, you need 3 days approximately.

Please mark me brainliest

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Complete the definition.
Sati [7]

Answer:

A relation has an input value which corresponds to an output value. When each input value has one and only one output value, that relation is a function. Functions can be written as ordered pairs, tables, or graphs. The set of input values is called the domain, and the set of output values is called the range.

Step-by-step explanation:

5 0
3 years ago
1. To calculate discretionary money, you ____?
sweet-ann [11.9K]
The answer to this question is letter a 
5 0
4 years ago
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I need help on this question ASAP pls
kirill [66]

Answer:

64/8

Step-by-step explanation: If a = 32 and b = 8, then the fraction turns into 2(32)/8.

2*32 is 64.

So, it turns into 64/8

You could also simplify it to 8/1, which is 8.

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3 years ago
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Can someone please help me with this statistics question?
stiks02 [169]
Probability of an event happening is given by:
probability of an event happening=number of ways it can happen/total number of outcomes
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7 0
4 years ago
The mayor gets elected every four years. Treasurer gets elected every six years. Both were elected this year. How many years bef
aleksandrvk [35]
<h3>There are 11 years before both the elections happen in the same year.</h3>

Step-by-step explanation:

The mayor gets selected once in every 4 years.

So, the number of years the mayor elections takes place

=  1, 4 ,8, 12, 16, 20, 24, 28,....

Now, the Treasurer gets selected once in every 6 years.

So, the number of years the Treasurer elections takes place

= 1,  6, 12, 18, 24, 30

Now,as we can see from both statements, the year in which both elections happen are the <u>common factors of 4 and 6.</u>

<u>The first common factor of 4 and 6 is 12. </u>

<u></u>

So,in twelfth year both elections happen in the same year again.

Hence, there are 11 years before the elections happen in the same year.

4 0
3 years ago
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