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Leto [7]
3 years ago
12

10 men who work 9hours per day, complete half of a work in 6days. How many days required for 15 men who work 12 hour per day to

complete the rest of the work ​
Mathematics
1 answer:
S_A_V [24]3 years ago
7 0

Answer:

So, you need 3 days approximately

Step-by-step explanation:

We will use Chain Rule to solve this question.

According to Chain Rule, the work efficiency remains constant.

• WWF×TWWF×T= Constant

• Here W = Work Done, WF = Workforce, T = Time.

Let the number of days  needed be 'x'.

Applying Chain Rule,

10×9×6= 15×12×(x)

Or, x=3x=3 day

So, you need 3 days approximately.

Please mark me brainliest

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A ships triangular signal flag has a base of 8 inches and an area of 64 square inches. What is the height of the signal flag
Firlakuza [10]
A = (1/2)bh
64 = (1/2)(8)h
16 = h
The height is 16 inches
7 0
3 years ago
Find the equation of the line<br> passing through the points 1,-5)<br> and (9,11).<br> y = 2x + [?]
Naily [24]

Answer:

y = 2x - 7

Step-by-step explanation:

Looks like we already have the slope of this line:  It is 2.  Working with the point (1, -5), we have x = 1 and y = -5 and can from this info easily find the y-intercept, b:

y = mx + b becomes

y  = 2x + b, which in turn becomes

-5 = 2(1) + b, or

b = -7,

and so the desired equation is y = 2x - 7

3 0
3 years ago
What is the value of cos(A) in the diagram?<br> a.60/61<br> b.61/11<br> c.11/61<br> d.61/60
ehidna [41]

Answer:

a. 60/61

Step-by-step explanation:

With reference angle A

base(b) = 60

hypotenuse (h) = 61

Now

Cos(A) = b / h

= 60/ 61

3 0
3 years ago
Read 2 more answers
Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> 500(1.075)120x = 100.000
Volgvan

Answer:

The solution is:

x = 0.61

Step-by-step explanation:

The first step to solve this equation is placing everything with the exponential to one side of the equality, and everything without the exponential to the other side. So

500(1.075)^{120x} = 100000

(1.075)^{120x} = \frac{100000}{500}

(1.075)^{120x} = 200

To find x, we have to apply log to both sides of the equality.

We also have that:

\log{a^{x}} = x\log{a}

So

\log{(1.075)^{120x}} = \log{200}

120x\log{1.075} = 2.30

120x*0.03 = 2.30

3.77x = 2.30

x = \frac{2.30}{3.77}

x = 0.61

4 0
3 years ago
Someone help please!!!!
LUCKY_DIMON [66]

Answer:

x = -2

TU = 4

UB = 2

Step-by-step explanation:

you can add x^2 with 4x+10 and equate it to 6:

x^2 + 4x + 10 = 6

x^2 + 4x + 4

then u can use the roots formula : x = (-b ± √ (b2 - 4ac) )/2a

so it'll be   x = {-4±[√16 - 4(4)]}/2

x= -2

then u can substitute it and find TU and UB

TU= (-2)^2 = 4

UB= 4(-2)+10 = 2

5 0
2 years ago
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