Mia is mixing nuts and cereal squares to make
1 answer:
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Answer:
D
Step-by-step explanation:
Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).
Consider option A.
1st transformation will map vertices of the square into points
2nd transformation = reflection over y = 1 has the rule (x,2-y). So,
These points are exactly the vertices of the initial square.
Consider option B.
1st transformation will map vertices of the square into points
2nd transformation = reflection over x = 3 has the rule (6-x,y). So,
These points are exactly the vertices of the initial square.
Consider option C.
1st transformation will map vertices of the square into points
2nd transformation = reflection over y = -x + 7 will map vertices into points
These points are exactly the vertices of the initial square.
Consider option D.
1st transformation will map vertices of the square into points
2nd transformation = reflection over y = -x + 2 will map vertices into points
These points are not the vertices of the initial square.