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3 years ago

20 points!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Firdavs [7]3 years ago

5 0

Answer: 320 FT^3

is the ans

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Vector B has x, y, and z components of 3, 7.2,

Temka [501]

Answer:

$\approx 9.0\:\mathrm{units}$

Step-by-step explanation:

The magnitude of 3D vector $\vec{v}$ can be given by the following:

$| \overline{v}| =\sqrt{{v_x}^2+{v_y}^2+{v_z}^2}$

Plugging in given values, we have:

$| \overline{v}|=\sqrt{3^2+7.2^2+4.5^2},\\| \overline{v}| \approx \fbox{$9.0\:\mathrm{units}$}$ .

6 0

3 years ago

Help me with this? ______________

Simora [160]

Answer:

Austin will have to buy 180 squares of carpeting.

Step-by-step explanation:

First find the dimension of the room. We do that by multiplying the width times the length and then subtracting the cut out region in the top right. And, in order to know how big that region we cut out is, we have to do a little subtraction.

We know the room is 18' long on the left side and 12' long on the right side. We subtract 12 from 18 to get 6, and we know that the cut out region is 6' long. We do the same thing with the width, 25' wide at the bottom minus 10' wide at the top and we see that the cut out is 15' wide.

18 x 25 = 450

6 x 15 = 90

450 - 90 = 360. The area of the room is 360 $ft^{2}$

Each piece of carpet is 2' by 1'. So for every 2' long, the piece of carpet is 1' wide. Each carpet piece will cover 2 $ft^{2}$ . Divide 360 by 2 and you get 180.

5 0

3 years ago

What is the length of the hypotenuse? If necessary, round to the nearest tenth.

azamat

By the Pythagorean theorem,

$a^{2}+12^{2}=13^{2}\\\\a^{2}+144=169\\\\a^{2}=25\\ \\ a=\boxed{5}$

4 0

2 years ago

Kill bought items costing $3.45,$1.99,$6.59 ,and $12.98. She used a coupon worth $2.50 .if Jill had $50.00 when she went into th

Alla [95]

First you add up all the items and the coupon then you will get $24.51. then subtract $50.00 take away $24.51 then you will get $25.49. So when she left the store she had $25.49

5 0

3 years ago

xand y are light house. y being 20km due east of x and from a ship due south of x the bearing of y was 055°. what is the distanc

leonid [27]

Answer:

I) |xz| ≈ 28.6 km

II) |yz| ≈ 34.8 km

Step-by-step explanation:

Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)

|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°

Using Trigonometric ratio - SOHCAHTOA

I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20

|xz| = 20 * Tan 55 = 20 * 1.428

|xz| = 28.56 km

|xz| ≈ 28.6 km

II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|

|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°

|yz| = 20 ÷ 0.574 = 34.84 km

|yz| ≈ 34.8 km

4 0

3 years ago