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valina [46]
3 years ago
11

A statement of an employee’s biweekly earnings is given below. What is the employee’s gross pay?

Mathematics
1 answer:
Olin [163]3 years ago
3 0
The employee's gross pay
$726.80
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What is the surface area of a cylinder with base radius 4 and height 5
mestny [16]
A=226.19 A=2πrh+2πr2=2·π·4·5+2·π·42≈226.19467
7 0
3 years ago
Which function is graphed below?
hoa [83]

Option B. y = 3 (one-third) Superscript x is the function that is graphed in this question.

<h3>How to solve the problem</h3>

We have exponential functions to be of the form abˣ

This can be written in the form of f(x) = 3\frac{1}{3} ^x

So it crosses through the point (0, 3).

From the way that the curve passes through the circle, we can see that the it is said to pass through at (0, 3) and approaches y = 0 in quadrant 1

Hence this would put our answer to be y = 3 (one-third) Superscript x

Read more on coordinate planes here

brainly.com/question/27975730?referrer=searchResults

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4 0
2 years ago
Read 2 more answers
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
Which shows the best estimate to use<br> to find 43 × 78?
Over [174]

Answer:

The best estimate for 43x78 is 40x80

Step-by-step explanation:

43 rounded to the nearest ten is 40.

78 rounded to the nearest ten is 80.  

The answer to 40x80 is 3200

4 0
3 years ago
Which of the following pairs of values for x and y would justify the claim that the two triangles are congruent? x = 3, y = 11 x
irinina [24]

Answer:

A

Step-by-step explanation:

just got it right

7 0
3 years ago
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