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Kruka [31]
3 years ago
14

Choose the correct simplification of f^9 h^23/f^3 h^17

Mathematics
1 answer:
Tanzania [10]3 years ago
4 0

Answer:

f6h40

Step-by-step explanation:

Step  1  :

           h23

Simplify   ———

           f3  

Equation at the end of step  1  :

         h23

 ((f9) • ———) • h17

         f3  

Step  2  :

Multiplying exponential expressions :

2.1    h23 multiplied by h17 = h(23 + 17) = h40

Final result :

 f6h40

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Naily [24]
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aivan3 [116]

Answer:

part A) The scale factor of the sides (small to large) is 1/2

part B) Te ratio of the areas (small to large) is 1/4

part C) see the explanation

Step-by-step explanation:

Part A) Determine the scale factor of the sides (small to large).

we know that

The dilation is a non rigid transformation that produce similar figures

If two figures are similar, then the ratio of its corresponding sides is proportional

so

Let

z ----> the scale factor

\frac{CB}{C'B'}=\frac{CD}{C'D'}=\frac{BD}{B'D'}

The scale factor is equal to

z=\frac{CB}{C'B'}

substitute

z=\frac{4}{8}

simplify

z=\frac{1}{2}

Part B) What is the ratio of the areas (small to large)?

<em>Area of the small triangle</em>

A=\frac{1}{2}(2)(4)=4\ units^2

<em>Area of the large triangle</em>

A=\frac{1}{2}(4)(8)=16\ units^2

ratio of the areas (small to large)

ratio=\frac{4}{16}=\frac{1}{4}

Part C) Write a generalization about the ratio of the sides and the ratio of the areas of similar figures

In similar figures the ratio of its corresponding sides is proportional and this ratio is called the scale factor

In similar figures the ratio of its areas is equal to the scale factor squared

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Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x? x = StartFraction negative 3 plus-or-
Brrunno [24]

Answer: FIRST OPTION

Step-by-step explanation:

<h3> The missing picture is attached.</h3>

By definition, given a Quadratic equation in the form:

ax^2+bx+c=0

Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.

The Quadratic Formula is the following:

x=\frac{-b \±\sqrt{b^2-4ac} }{2a}

In this case, the exercise gives you this Quadratic equation:

5x^2 + 3x - 4 = 0

You can identify that the numerical coefficients are:

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Therefore, you can substitute values into the Quadratic formula shown above:

x=\frac{-b \±\sqrt{b^2-4ac} }{2a}\\\\x=\frac{-3 \±\sqrt{(3)^2-4(5)(-4)} }{2(5)}

You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.

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