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3 years ago

Describe a sequence of transformations that takes trapezoid A to trapezoid B

Mathematics

1 answer:

marin [14]3 years ago

3 0

Answer:

How do you describe the sequence of transformations?

Image result for Describe a sequence of transformations that takes trapezoid A to trapezoid B

When two or more transformations are combined to form a new transformation, the result is called a sequence of transformations, or a composition of transformations. Remember, that in a composition, one transformation produces an image upon which the other transformation is then performed.

Step-by-step explanation:

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each day last week, Ms. wilson walked3/4 mile. what is the total distance, in miles, that Ms. Wilson walked in 4 days?

zloy xaker [14]

Hey there! :D

Since she walks 3/4 a mile a day, we can multiply that by 4.

3/4= .75

4*.75= 3

She walked 3 miles in 4 days.

I hope this helps!
~kaikers

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3 years ago

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Anyone help with these 2 question?

ICE Princess25 [194]

Step-by-step explanation:

1.√2×(-2√9)×(-√2)

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3 years ago

Solve for x 3^x+4=9 3 to the power of x plus 4 is equal to 9

Bingel [31]

$3^{x} + 4 = 9 \\3^{x} = 5 \\ln(3^{x}) = ln(5) \\xln(3) = ln(5) \\\frac{xln(3)}{ln(3)} = \frac{ln(5)}{ln(3)} \\x = \frac{ln(5)}{ln(3)}$

or

$3^{x + 4} = 9 \\ln(3^{x + 4}) = ln(9) \\(x + 4)ln(3) = ln(9) \\\frac{(x + 4)ln(3)}{ln(3)} = \frac{ln(9)}{ln(3)} \\x + 4 = \frac{ln(3^{2})}{ln(3)} \\x + 4 = \frac{2ln(3)}{ln(3)} \\x + 4 = 2 \\x = -2$

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4 years ago

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statuscvo [17]

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Step-by-step explanation:

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3 years ago

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This trapezium is drawn on a centimetre grid. Find the area of the trapezium.

aivan3 [116]

Answer:

20 unit²

Step-by-step explanation:

A trapezium is given to us on the grid and we need to find out the area of the trapezium . In order to find the area , we need to find the measure of the parallel sides and the distance between the parallel sides.

From the grid :-

$\rm\implies Side_1 = 7 \ units$

$\rm\implies Side_2 = 3 \ units$

$\rm\implies \perp \ Distance =4 \ units$

Now here we got the two parallel sides of the trapezium and the distance between the two parallel sides. Now we can find the area as ,

$\rm\implies Area_{Trapezium}= \dfrac{1}{2}\times ( s_1 + s_2) \times \perp \ Distance \\\\\rm\implies Area = \dfrac{1}{2} \times ( 7 + 3 ) \times 4 \ unit^2 \\\\\rm\implies Area = \dfrac{1}{2} \times ( 10) \times 4 \ unit^2 \\\\\rm\implies\boxed{\rm Area = 20 \ unit^2}$

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3 years ago