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3 years ago

Is x=-2 a positive slope

Mathematics

1 answer:

victus00 [196]3 years ago

7 0

Answer:

Step-by-step explanation:

x = -2 represents a vertical line that intersects the x axis at the point (-2, 0). Since the line is vertical, the slope is undefined making it not have a positive slope.

Best of Luck!

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Select the correct answer.

leonid [27]

Answer:

a) √500

Step-by-step explanation:

I hope it will help you

5 0

3 years ago

hot dogs are sold in packages of 10 and hot dog buns are sold in packs of 8 Tommy wants to know the least number of packs of hot

enot [183]

Answer:

4 packs of hotdogs, 5 packs of buns

Step-by-step explanation:

In this case, we need to find the LCM, least common multiple, of 8 and 10 to find the least number of packs of hot dogs and buns that Tommy needs to buy.

The LCM of 8 and 10 is the smallest number that is both divisible by 8 and 10. One way we can find this is by checking all the multiples of 10 in ascending order to see if they are divisble by 8:

10 is not divisible by 8

20 is not divisible by 8

30 is not divisible by 8

40 is divisible by 8!

Therefore, Tommy will need to by 40 buns and 40 hotdogs. Since buns come in packs of 8 and hot dogs come in packs of 10, we can divide to get the number of packs Tommy should buy respectively:

$40$ ÷ $10=4$ packs of hotdogs

$40$ ÷ $8=5$ packs of buns

Tommy will need to buy 4 packs of hotdogs and 5 packs of buns so that he does not have anything left over.

I hope this helps! Let me know if you have any questions :)

4 0

3 years ago

Please help!!!!!!!!!!!!!!!!!!

elena55 [62]

$h(x)=(f\circ g)(x)\\\\h(x)=\sqrt[3]{x+3};\ f(x)=\sqrt[3]{x+2}\\\\h(x)=\sqrt[3]{x+1+2}=\sqrt[3]{(x+1)+2}=\sqrt[3]{g(x)+2}\to \boxed{g(x)=x+1}$

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$f(x)=2x;\ g(x)=2x-1;\ h(x)=\sqrt{x}\\\\(f\circ g\circ h)(9)=?\\\\h(9)=\sqrt9=3\\\\(g\circ h)(9)=g(3)=2(3)-1=6-1=5\\\\(f\circ g\circ h)(9)=f(5)=2(5)=10\\------------------------------\\other\ method:\\\\(f\circ g\circ h)(x)=2(2\sqrt{x}-1)=4\sqrt{x}-2\\\\(f\circ g\circ h)(9)=4\sqrt9-2=4(3)-2=12-2=10$

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$f(x)=4x+1;\ g(x)=x^2-5\\\\(f\circ g)(4)=?\\\\g(4)=4^2-5=16-5=11\\(f\circ g)(4)=f(11)=4(11)+1=44+1=45\\----------------------------------\\other\ method:\\\\(f\circ g)(x)=4(x^2-5)+1=4x^2-20+1=4x^2-19\\\\(f\circ g)(4)=4(4)^2-19=4(16)-19=64-19=45$

8 0

3 years ago

How far in feet will a child on the edge of the merry-go-round travel? If r=6 feet, the angle is 310

goblinko [34]

Answer:

First some theory we need to solve this problem.

For a circle of radius R, the perimeter is:

P = 2*pi*R

where pi = 3.14

If we have a section of this circle, defined by an angle θ, the length of this arc will be:

A = (θ/360°)*2*pi*R

In the case of the problem, the total distance that the child travels is equal to the length of an arc of 310° in a circle of radius r = 6ft.

Using the above formula, we know that the length of this arc is:

A = (310°/360°)*2*3.14*(6ft) = 32.4 ft

7 0

3 years ago

Can someone please help im big dum!?

mezya [45]

Answer:

1st answer is correct yourwelcome

4 0

3 years ago

Read 2 more answers