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Trava [24]
2 years ago
7

How do you solve this?

Mathematics
1 answer:
Arturiano [62]2 years ago
3 0

Answer:

x=-5

Step-by-step explanation:

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The sides of a right triangle are x, x+21, and x+27. what is the length of the hypotenuse
mina [271]
Answer: 51 uinits

The three numbers are x , x + 21 and x + 27. 
The greatest of the 3 numbers is x + 27, so x + 27 has to be the hypotenuse.

----------------------------------------------
Pythagoras Theorem
----------------------------------------------

a² + b²  = c²

x² + (x+21)² = (x+27)²

x² + x² + 42x + 441 = x² + 54x + 729

x² - 12x -288 = 0

(x - 24)(x + 12) = 0

x = 24 or x = -12 (rejected, length cannot be negative)

----------------------------------------------
Find hypotenuse
----------------------------------------------
 Hypotenuse = x + 27 = 24 + 27 = 51 units

-----------------------------------------------
Answer: 51 units
----------------------------------------------

3 0
3 years ago
Read 2 more answers
Take a look at the picture and answer correctly so i can mark you as brainliest.
klio [65]

Answer:

{2, 3}

Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
Hank purchase 98 shirts for school each shirt cost $12.80 after tax what was the total price for a 76 shirts
marusya05 [52]

Answer:

$972.8

Step-by-step explanation:

$12.80 x 76 = $972.8

3 0
2 years ago
Kevin earned $80. Out of his earnings, he spent $68/5 on shopping, $51/2 on food, and $22/5 for taxi. Find the remaining amount.
Assoli18 [71]

The amount remaining out the money earned is $37.5

<h3>Sum of values and proportion</h3>

Given the following parameters

Amount earned by kevin = $80

If he spent $68/5 on shopping, $51/2 on food, and $22/5 for taxi, the total money spent is given as;

Total money spent = 51/2 + 68/5 + 22/5

Total money spent = 51/2 + 90/5

Total money spent = 25.5 + 18

Total money spent = 43.5

Amount remaining = 80. - 43.5

Amount remaining = 37.5

Hence the amount remaining out the money earned is $37.5

Learn more on difference here: brainly.com/question/148825

#SPJ1

3 0
2 years ago
Let T:P3→P3 be the linear transformation such that T(â’2x2)=3x2+4x, T(0.5x+3)=â’3x2+3xâ’4, and T(2x2â’1)=â’3x+4. Find T(1), T(
balu736 [363]

It looks like we're told that

T(-2x^2)=3x^2+4x

T\left(\dfrac12x+3\right)=-3x^2+3x-4

T(2x^2-1)=-3x+4

We use the fact that T is linear to find T(1),T(x),T(x^2). First, we notice that

T(-2x^2)+T(2x^2-1)=T(-2x^2+2x^2-1)=T(-1)=-T(1)

We also have

T\left(\dfrac12x+3\right)=T\left(\dfrac12x\right)+T(3)=\dfrac12T(x)+3T(1)

T(2x^2-1)=T(2x^2)-T(1)=2T(x^2)-T(1)

So once we find T(1), we can determine T(x) and T(x^2). We have

T(1)=-\left(T(-2x^2)+T(2x^2-1)\right)\implies T(1)=-3x^2-x-4

and using this we find

T(x)=12x^2+12x+16

T(x^2)=-\dfrac32x^2-2x

Then

T(ax^2+bx+c)=T(ax^2)+T(bx)+T(c)=aT(x^2)+bT(x)+cT(1)

T(ax^2+bx+c)=-\dfrac32\left(a-8b+2c\right)x^2-(2a-12b+c)x+16b-4c

8 0
3 years ago
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