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1 year ago

What are the intercepts of the graph of the equation, y=-7

Mathematics

1 answer:

goldenfox [79]1 year ago

7 0

Answer:

y-7=0 is the same as y=7

The drawing of y=7 is a straight horizontal line intercepting the y axis at 7. So basically it's a horizontal line that passes through (0,7). Its slope is zero since it's a horizontal line.

Step by step explanation:

A line with no x in the equation is a horizontal line. In this case, y=7. All horizontal lines have a slope of 0, since there is never a change in the y coordinate (it is always 7) so the numerator of the fraction used to determine the slope is 0.

The y-intercept is, of course 7 (all y values on the line are 7). There is no x-intercept since it is a horizontal line through the point (0,7) so it will never intersect the x-axis.

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anyanavicka [17]

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2 years ago

What is −4(−5x+2)−3x−5= -30

alexandr1967 [171]

Answer:

x = -1

Step-by-step explanation:

Step 1: Write equation

-4(-5x + 2) - 3x - 5 = -30

Step 2: Solve for x

Distribute -4: 20x - 8 - 3x - 5 = -30

Combine like terms: 17x - 13 = -30

Add 13 on both sides: 17x = -17

Divide both sides by 17: x = -1

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2 years ago

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Solve,justify and check: 3(7+5n)=6n+6(1+4n)

vlabodo [156]

Answer:

1=n

Step-by-step explanation:

Step 1- Distribute into the parenthesis.

7(3)+5(3)n= 6n+1(6)+4(6)n

Step 2- Multiply

21+15n= 6n+6+24n

Step 3- Add common variables to simplify.

21+15n= (24n+6n)+6

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Step 4- Subtract the smallest variable to both sides.

21+15n= 30n+6

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21= 15n+6

Step 5- Subtract 6 to both sides.

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3 years ago

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The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that $n = 300$ and $\pi = \frac{10}{300} = 0.033$

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So $\alpha$ = 0.05, z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532$

The correct answer is

(0.0128, 0.0532)

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2 years ago

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denis-greek [22]

I didn't know what you meant by phrase, so I put in a few:

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3 years ago

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