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Vedmedyk [2.9K]
3 years ago
12

Which sets are not closed under subtraction

Mathematics
1 answer:
anastassius [24]3 years ago
6 0

If you're referring to the different sets of real numbers, it's the ones that you could try to do subtraction and not get an answer that still in that set.

For example, natural numbers (aka 1, 2, 3, 4, ...) are not, because 7 - 11 = -4 and -4 is not a natural number.

Also, whole numbers (aka 0, 1, 2, 3, 4, ...) has the same issue.

Basically any set of real numbers that doesn't include negative numbers will have this issue.

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Someone please help me figure this question out!!
rosijanka [135]
If you subtract 1.1 from 5.8 you will end up with 4.7
then you subtract 10^7 from 10^8 which will give you 10^1 
then you add the seven back which will give you your answer of 
4.7 10^8
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=7x%20%2B%202%20%3D%202" id="TexFormula1" title="7x + 2 = 2" alt="7x + 2 = 2" align="absmiddle"
Anastaziya [24]
Easy.

7x + 2 = 2

7x = 2 - 2

7x = 0

x = 0 / 7

x = 0

Verify this by putting x = 0 ...

7 ( 0 ) + 2 = 2

0 + 2 = 2

2 = 2

Hence, "0" is the final answer.

Hope helps ........
4 0
3 years ago
The coordinates of the vertices of a polygon are shown on the grid below​
AnnZ [28]
Uhm Where is the grid?
5 0
3 years ago
PLz answer before 11:59 pm
Tpy6a [65]

Answer:

SA = 2520 ft^2

Step-by-step explanation:

a = 21ft

b = 29ft

c = 20ft

h = 30ft

SA = 2A_{B} + (a+b+c)h

A_{B} = s(s﹣a)(s﹣b)(s﹣c)

s = \frac{a + b + c}{2}

SA= ah + bh + ch + \frac{1}{2} \sqrt{-a^4 + 2(ab)^2 + 2(ac)^2 - b^4 + 2(bc)^2 - c4}

SA= (21 * 30) + (29 * 30) + (20 * 30) +

       \frac{1}{2} \sqrt{-(21)^4 + 2(21 * 29)^2 + 2(21 * 20)^2 - (29)^4 + 2(29 * 20)^2 - (20)^4}

SA = 2520 ft^2

6 0
3 years ago
What is 2(-a-8) + 7a​
ella [17]

Answer:

a = 3.2

Step-by-step explanation:

2( -a - 8) + 7a = 0

-2a -16 + 7a = 0

5a - 16 = 0

5a = 16

a = 16/5

a = 3.2

5 0
3 years ago
Read 2 more answers
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