Hi

Left to do 40% of the shopping

12 items ⇒ 60% of the items
x items ⇒ 40% of the items

60x = 12(40)
60x = 480
x = 480/60
x = 48/6
x = 8 items

Answer:

Left 8 items of the list (40% of the shopping)

Items: 12+8 = 20 items on her list

4 0

3 years ago

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What are the dimensions of the matrix?

salantis [7]

The order of a matrix is m×n where m is the number of rows and n is the number of columns.

can you count and find what are m and n here?

6 0

3 years ago

How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t

Zarrin [17]

By first principles, the derivative is

$\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h$

Use the binomial theorem to expand the numerator:

$(x+h)^n=\displaystyle\sum_{i=0}^n\binom nix^{n-i}h^i=\binom n0x^n+\binom n1x^{n-1}h+\cdots+\binom nnh^n$

$(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n$

where

$\dbinom nk=\dfrac{n!}{k!(n-k)!}$

The first term is eliminated, and the limit is

$\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h$

A power of $h$ in every term of the numerator cancels with $h$ in the denominator:

$\displaystyle\lim_{h\to0}\left(nx^{n-1}+\dfrac{n(n-1)}2x^{n-2}h+\cdots+nxh^{n-2}+h^{n-1}\right)$

Finally, each term containing $h$ approaches 0 as $h\to0$ , and the derivative is

$y=x^n\implies y'=nx^{n-1}$

4 0

3 years ago

How else can the ratio 14:1 be written?<br> A. 1.4<br> B. 14/1<br> C.1/14<br> D. 1:14

lukranit [14]

Answer:

Step-by-step explanation:

5 0

3 years ago

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