Answer:
<h2> In 8 hours he will set 1200 bricks</h2>
Step-by-step explanation:
In this problem, we are expected to estimate the number of bricks he can set in 8 hours.
let us convert hours to minutes we have
60 min make 1 hour
x min make 8 hours
cross multiply
x= 60*8
x= 480 min
We are assuming the same rate with which he sets 2.5 brick is the same as the rate with which he will set bricks for the 8 hours windows
so if the bricklayer sets
2.5 bricks in 1min
y bricks in 480 min
Cross multiply we have
y=2.5*480
y= 1200 bricks
hence in 8 hours, he will set 1200 bricks
Answer:
see explanation
Step-by-step explanation:
The common difference d of an arithmetic sequence is
d = - = -
Substitute in values and solve for k, that is
5k - 1 - 2k = 6k + 2 - (5k - 1)
3k - 1 = 6k + 2 - 5k + 1
3k - 1 = k + 3 ( subtract k from both sides )
2k - 1 = 3 ( add 1 to both sides )
2k = 4 ⇒ k = 2
--------------------------------------------------------
The n th term of an arithmetic sequence is
= + (n - 1)d
= 2k = 2 × 2 = 4 and
d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5
Hence
= 4 + (7 × 5) = 4 + 35 = 39
Answer:
The population will reach 34,200 in February of 2146.
Step-by-step explanation:
Population in t years after 2012 is given by:
In what month and year will the population reach 34,200?
We have to find t for which P(t) = 34200. So
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots such that , given by the following formulas:
In this question:
So
Then
We only take the positive value.
134 years after 2012.
.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.
So the population will reach 34,200 in February of 2146.