5. Find dy/dx of of the followingthe following functionsy²= 4ax
1 answer:
Answer:
A general rule for functions of the general form:
y = A*x^n
is:
dy/dx = n*A*x^(n - 1)
Then, for the function:
y^2 = 4*a*x
Then we can rewrite this as:
y = (4*a*x)^(1/2) = √(4*a)*x^(1/2)
Then we have:
A = √(4*a)
n = 1/2
Now we can use the above rule to get
dy/dx = (1/2)*√(4*a)*x^(1/2 - 1)
dy/dx = (1/2)*√(4*a)*x^(-1/2)
dy/dx = (1/2)*√(4*a/x)
dy/dx = √(1/4)*√(4*a/x)
dy/dx = √( (1/4)*4*a/x)
dy/dx = √(a/x)
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It is in form
0=ax^2+bx+c
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c=6
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Answer:
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Answer:
Domain(x-values) Pls mark brainliest :)
Step-by-step explanation:
Answer:
2x - 6y
Step-by-step explanation:
(5x – 2y) – (3x + 4y)
5x - 2y - (3x + 4y)
Distribute the - sign
5x - 2y - 3x - 4y
Group like terms
(5x - 3x) + (-2y - 4y)
Combine like term
2x - 6y