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Makovka662 [10]
2 years ago
7

5. Find dy/dx of of the followingthe following functionsy²= 4ax​

Mathematics
1 answer:
ivolga24 [154]2 years ago
8 0

Answer:

A general rule for functions of the general form:

y = A*x^n

is:

dy/dx =  n*A*x^(n - 1)

Then, for the function:

y^2 = 4*a*x

Then we can rewrite this as:

y = (4*a*x)^(1/2) = √(4*a)*x^(1/2)

Then we have:

A = √(4*a)

n = 1/2

Now we can use the above rule to get

dy/dx = (1/2)*√(4*a)*x^(1/2 - 1)

dy/dx = (1/2)*√(4*a)*x^(-1/2)

dy/dx = (1/2)*√(4*a/x)

dy/dx = √(1/4)*√(4*a/x)

dy/dx = √( (1/4)*4*a/x)

dy/dx = √(a/x)

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