So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:
Next, square both sides:
Next, subtract x and add 2 to both sides of the equation:
Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:
Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now you can rewrite the equation as
Now, apply the Zero Product Property and solve for x as such:
Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:
Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>
Answer:
red
Step-by-step explanation:
1-red
2-blue
3-red
4-blue
5-red
6-blue
7-red
8-blue
9-red
10-blue
11-red
12-blue
13-red
14-blue
15-red
16-blue
17-red
18-blue
19-red
20-blue
21-red
22-blue
23-red
im so smart fr
1.)-3y=2* -3-9
-3y=-6-9
-3y=-15
y=5
-3*5=-15
2.)-3y=2*0-9
-3y=0-9
-3y=-9
y=3
-3*3=-9
3.)-3y=2*3-9
-3y=6-9
-3y=-3
y=1
-3*1=-3
Answer:
b
Step-by-step explanation:
The sum of angles in a triangle is 180°. Therefore,
x - 11 + 48 + 90 = 180
x + 127 = 180
x = 53°