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siniylev [52]
3 years ago
12

Plz help me(A lot of points if correct)

Mathematics
1 answer:
Sindrei [870]3 years ago
8 0

Answer:

∴At the beginning of the game Sparrow had = (70+12)=82 coins

Step-by-step explanation:

Given , three pirates named Ahab, Sparrow and Davy play a game.

Let at the end of the game Ahab, Sparrow and Davy  have 4x, 5x,and 6x coins respectively.

Total number of coins= 4x+5x+6x=15x

Again given that the pirates have a total of 210 coins.

According to the problem,

15x =210

⇔x = 14

Therefore, Ahab, Sparrow and Davy  have(4×14)=56,(5×14)=70 and (6×14)=84 respectively.

Since,Ahab has won 5 coins and Davy has won 7 coins.This(7+5)=12 coins was belonged to Sparrow.

∴At the beginning of the game Sparrow had = (70+12)=82 coins

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