Answer:
∴At the beginning of the game Sparrow had = (70+12)=82 coins
Step-by-step explanation:
Given , three pirates named Ahab, Sparrow and Davy play a game.
Let at the end of the game Ahab, Sparrow and Davy have 4x, 5x,and 6x coins respectively.
Total number of coins= 4x+5x+6x=15x
Again given that the pirates have a total of 210 coins.
According to the problem,
15x =210
⇔x = 14
Therefore, Ahab, Sparrow and Davy have(4×14)=56,(5×14)=70 and (6×14)=84 respectively.
Since,Ahab has won 5 coins and Davy has won 7 coins.This(7+5)=12 coins was belonged to Sparrow.
∴At the beginning of the game Sparrow had = (70+12)=82 coins
