Answer:
<u>BEST</u>
Option 4
<u>WORST</u>
2
Explanation:
Option 4 is the best cus confronting is better than just watching and letting it happen which in option 2 that's the case
Answer:
Explanation:
Given
Required
Determine 
implies 10th percentile and this is calculated as thus
Where n is the number of data; n = 14
Substitute 14 for n
Open the bracket
This means that the 1.5th item is
And this falls between the 1st and 2nd item and is calculated as thus;
Express 1.5 as 1 + 0.5
From the given data; 
and 
becomes
Answer:
The solution code is written in Python 3:
- import keyword
-
- def checkValidVariable(string):
- if(not keyword.iskeyword(string)):
- return True
- else:
- return False
-
- print(checkValidVariable("ABC"))
- print(checkValidVariable("assert"))
Explanation:
Firstly, we need to import keyword module so that we can use its iskeyword method to check if a string is registered as Python keyword (Line 1).
Next, we create a function checkValidVariable that takes one input string (Line 3). Within the function body, we use iskeyword method to check if the input string is keyword. Please note the "not" operator is used here. So, if iskeyword return True, the True value will be turned to False by the "not" operator or vice versa (Line 4-5).
We test the function by passing two input string (Line 9-10) and we shall get the sample output as follows:
True
False
Answer:
In Python:
low = int(input("Low: "))
high = int(input("High: "))
if low >= 1000000000 or high >=1000000000:
print("Out of range")
else:
mylist = []
for num in range(low,high+1):
flag = False
if num > 1:
for i in range(2, num):
if (num % i) == 0:
flag = True
break
if not flag:
mylist.append(num)
print(num, end = " ")
print()
print("The twin primes are: ",end="")
count = 0
for i in range(1,len(mylist)):
if mylist[i] - mylist[i-1] == 2:
print(str(mylist[i])+" & "+str(mylist[i-1]),end=", ")
count+=1
print()
print("There are "+str(count)+" twin primes")
Explanation:
See attachment for complete program where comments were used to explain each line
