Sets and set operations are ways of organizing, classifying and obtaining information about objects according to the characteristics they possess, as objects generally have several characteristics, the same object can belong to several sets, an example is the subjects of a school , where students (objects) are classified according to the subject they study (set).
The <em>intersection</em> of sets is a new set consisting of those objects that simultaneously possess the characteristics of each intersected set, the intersection of two subjects will be those students who have both subjects enrolled.
The <em>union</em> of sets is a new set consisting of all the objects belonging to the united sets, the union of two subjects will be all students of both courses.
In this case there are three sets B, C and S of which we are given the following information:
Answer
n(BꓵSꓵC)=5
n(BꓵS)=10 – 5 = 5
n(BꓵC)=12 – 5 = 7
n[(BꓵC)ꓴ(BꓵS)ꓴ(CꓵS)]=21 – 5 – 5 – 7 = 4
n(B)=36 – 5 – 5 – 7 = 19
n(S)=30 – 5 – 5 – 4 = 16
n(C)=34 – 5 – 7 – 4 = 18
The equation of a line that passes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so
we see that the slope is rise/run=3/4
3 points we see are (-4,-6), (0,-3) and (4,0)
we get the equations
y+6=3/4(x+4)
y+3=3/4(x+0)
y+0=3/4(x+4)
answer is the first equaiton
y+6=3/4(x+4)
Last year He was 7 years old.
His father is 4 times the age 7 x 4 = 28
Last year his dad was 28, so this year he is 29.
Combined age this year = 29 + 8 = 37
51 - 37 = 14 years
14/ 2 people = 7 years
8 + 7 = 15
29 + 7 = 36
15 + 36 = 51
It will take 7 years.
W has 1 line of symmetry- right down the middle. Nowhere else on the figure can it be reflected into symmetry.
Answer:
The answer would be C (3,-2)
Step-by-step explanation: