Question

In the adjoining figure O is the centre of the circle the tangent to the circle of radius 6 cm from the exterior point P of the length 8 cm calculate the distance of the point P from the centre o
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Answer 1

Answer:

Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.

Let Q be the point onthe circle  in which, tangent make 90° with radius at Q.

PQ = 8 and OQ = 6

we get a right angled triangle  PQO right angled at Q.

so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==

therefore OP =10cm

we need nearest point from P, which is PA

PA = OP - OA= 10 -6=4cm